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NaOH + FeSO4 + NaClO = H2O + NaCl + Na2SO4 + Na2FeO4

Input interpretation

NaOH sodium hydroxide + FeSO_4 duretter + NaOCl sodium hypochlorite ⟶ H_2O water + NaCl sodium chloride + Na_2SO_4 sodium sulfate + Na2FeO4
NaOH sodium hydroxide + FeSO_4 duretter + NaOCl sodium hypochlorite ⟶ H_2O water + NaCl sodium chloride + Na_2SO_4 sodium sulfate + Na2FeO4

Balanced equation

Balance the chemical equation algebraically: NaOH + FeSO_4 + NaOCl ⟶ H_2O + NaCl + Na_2SO_4 + Na2FeO4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 FeSO_4 + c_3 NaOCl ⟶ c_4 H_2O + c_5 NaCl + c_6 Na_2SO_4 + c_7 Na2FeO4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, Fe, S and Cl: H: | c_1 = 2 c_4 Na: | c_1 + c_3 = c_5 + 2 c_6 + 2 c_7 O: | c_1 + 4 c_2 + c_3 = c_4 + 4 c_6 + 4 c_7 Fe: | c_2 = c_7 S: | c_2 = c_6 Cl: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 2 c_4 = 2 c_5 = 2 c_6 = 1 c_7 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 NaOH + FeSO_4 + 2 NaOCl ⟶ 2 H_2O + 2 NaCl + Na_2SO_4 + Na2FeO4
Balance the chemical equation algebraically: NaOH + FeSO_4 + NaOCl ⟶ H_2O + NaCl + Na_2SO_4 + Na2FeO4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 FeSO_4 + c_3 NaOCl ⟶ c_4 H_2O + c_5 NaCl + c_6 Na_2SO_4 + c_7 Na2FeO4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, Fe, S and Cl: H: | c_1 = 2 c_4 Na: | c_1 + c_3 = c_5 + 2 c_6 + 2 c_7 O: | c_1 + 4 c_2 + c_3 = c_4 + 4 c_6 + 4 c_7 Fe: | c_2 = c_7 S: | c_2 = c_6 Cl: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 2 c_4 = 2 c_5 = 2 c_6 = 1 c_7 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 NaOH + FeSO_4 + 2 NaOCl ⟶ 2 H_2O + 2 NaCl + Na_2SO_4 + Na2FeO4

Structures

+ + ⟶ + + + Na2FeO4
+ + ⟶ + + + Na2FeO4

Names

sodium hydroxide + duretter + sodium hypochlorite ⟶ water + sodium chloride + sodium sulfate + Na2FeO4
sodium hydroxide + duretter + sodium hypochlorite ⟶ water + sodium chloride + sodium sulfate + Na2FeO4

Equilibrium constant

Construct the equilibrium constant, K, expression for: NaOH + FeSO_4 + NaOCl ⟶ H_2O + NaCl + Na_2SO_4 + Na2FeO4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 4 NaOH + FeSO_4 + 2 NaOCl ⟶ 2 H_2O + 2 NaCl + Na_2SO_4 + Na2FeO4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 4 | -4 FeSO_4 | 1 | -1 NaOCl | 2 | -2 H_2O | 2 | 2 NaCl | 2 | 2 Na_2SO_4 | 1 | 1 Na2FeO4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 4 | -4 | ([NaOH])^(-4) FeSO_4 | 1 | -1 | ([FeSO4])^(-1) NaOCl | 2 | -2 | ([NaOCl])^(-2) H_2O | 2 | 2 | ([H2O])^2 NaCl | 2 | 2 | ([NaCl])^2 Na_2SO_4 | 1 | 1 | [Na2SO4] Na2FeO4 | 1 | 1 | [Na2FeO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-4) ([FeSO4])^(-1) ([NaOCl])^(-2) ([H2O])^2 ([NaCl])^2 [Na2SO4] [Na2FeO4] = (([H2O])^2 ([NaCl])^2 [Na2SO4] [Na2FeO4])/(([NaOH])^4 [FeSO4] ([NaOCl])^2)
Construct the equilibrium constant, K, expression for: NaOH + FeSO_4 + NaOCl ⟶ H_2O + NaCl + Na_2SO_4 + Na2FeO4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 4 NaOH + FeSO_4 + 2 NaOCl ⟶ 2 H_2O + 2 NaCl + Na_2SO_4 + Na2FeO4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 4 | -4 FeSO_4 | 1 | -1 NaOCl | 2 | -2 H_2O | 2 | 2 NaCl | 2 | 2 Na_2SO_4 | 1 | 1 Na2FeO4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 4 | -4 | ([NaOH])^(-4) FeSO_4 | 1 | -1 | ([FeSO4])^(-1) NaOCl | 2 | -2 | ([NaOCl])^(-2) H_2O | 2 | 2 | ([H2O])^2 NaCl | 2 | 2 | ([NaCl])^2 Na_2SO_4 | 1 | 1 | [Na2SO4] Na2FeO4 | 1 | 1 | [Na2FeO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-4) ([FeSO4])^(-1) ([NaOCl])^(-2) ([H2O])^2 ([NaCl])^2 [Na2SO4] [Na2FeO4] = (([H2O])^2 ([NaCl])^2 [Na2SO4] [Na2FeO4])/(([NaOH])^4 [FeSO4] ([NaOCl])^2)

Rate of reaction

Construct the rate of reaction expression for: NaOH + FeSO_4 + NaOCl ⟶ H_2O + NaCl + Na_2SO_4 + Na2FeO4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 4 NaOH + FeSO_4 + 2 NaOCl ⟶ 2 H_2O + 2 NaCl + Na_2SO_4 + Na2FeO4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 4 | -4 FeSO_4 | 1 | -1 NaOCl | 2 | -2 H_2O | 2 | 2 NaCl | 2 | 2 Na_2SO_4 | 1 | 1 Na2FeO4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 4 | -4 | -1/4 (Δ[NaOH])/(Δt) FeSO_4 | 1 | -1 | -(Δ[FeSO4])/(Δt) NaOCl | 2 | -2 | -1/2 (Δ[NaOCl])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) NaCl | 2 | 2 | 1/2 (Δ[NaCl])/(Δt) Na_2SO_4 | 1 | 1 | (Δ[Na2SO4])/(Δt) Na2FeO4 | 1 | 1 | (Δ[Na2FeO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/4 (Δ[NaOH])/(Δt) = -(Δ[FeSO4])/(Δt) = -1/2 (Δ[NaOCl])/(Δt) = 1/2 (Δ[H2O])/(Δt) = 1/2 (Δ[NaCl])/(Δt) = (Δ[Na2SO4])/(Δt) = (Δ[Na2FeO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NaOH + FeSO_4 + NaOCl ⟶ H_2O + NaCl + Na_2SO_4 + Na2FeO4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 4 NaOH + FeSO_4 + 2 NaOCl ⟶ 2 H_2O + 2 NaCl + Na_2SO_4 + Na2FeO4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 4 | -4 FeSO_4 | 1 | -1 NaOCl | 2 | -2 H_2O | 2 | 2 NaCl | 2 | 2 Na_2SO_4 | 1 | 1 Na2FeO4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 4 | -4 | -1/4 (Δ[NaOH])/(Δt) FeSO_4 | 1 | -1 | -(Δ[FeSO4])/(Δt) NaOCl | 2 | -2 | -1/2 (Δ[NaOCl])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) NaCl | 2 | 2 | 1/2 (Δ[NaCl])/(Δt) Na_2SO_4 | 1 | 1 | (Δ[Na2SO4])/(Δt) Na2FeO4 | 1 | 1 | (Δ[Na2FeO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/4 (Δ[NaOH])/(Δt) = -(Δ[FeSO4])/(Δt) = -1/2 (Δ[NaOCl])/(Δt) = 1/2 (Δ[H2O])/(Δt) = 1/2 (Δ[NaCl])/(Δt) = (Δ[Na2SO4])/(Δt) = (Δ[Na2FeO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| sodium hydroxide | duretter | sodium hypochlorite | water | sodium chloride | sodium sulfate | Na2FeO4 formula | NaOH | FeSO_4 | NaOCl | H_2O | NaCl | Na_2SO_4 | Na2FeO4 Hill formula | HNaO | FeO_4S | ClNaO | H_2O | ClNa | Na_2O_4S | FeNa2O4 name | sodium hydroxide | duretter | sodium hypochlorite | water | sodium chloride | sodium sulfate | IUPAC name | sodium hydroxide | iron(+2) cation sulfate | sodium hypochlorite | water | sodium chloride | disodium sulfate |
| sodium hydroxide | duretter | sodium hypochlorite | water | sodium chloride | sodium sulfate | Na2FeO4 formula | NaOH | FeSO_4 | NaOCl | H_2O | NaCl | Na_2SO_4 | Na2FeO4 Hill formula | HNaO | FeO_4S | ClNaO | H_2O | ClNa | Na_2O_4S | FeNa2O4 name | sodium hydroxide | duretter | sodium hypochlorite | water | sodium chloride | sodium sulfate | IUPAC name | sodium hydroxide | iron(+2) cation sulfate | sodium hypochlorite | water | sodium chloride | disodium sulfate |

Substance properties

| sodium hydroxide | duretter | sodium hypochlorite | water | sodium chloride | sodium sulfate | Na2FeO4 molar mass | 39.997 g/mol | 151.9 g/mol | 74.44 g/mol | 18.015 g/mol | 58.44 g/mol | 142.04 g/mol | 165.82 g/mol phase | solid (at STP) | | liquid (at STP) | liquid (at STP) | solid (at STP) | solid (at STP) | melting point | 323 °C | | -6 °C | 0 °C | 801 °C | 884 °C | boiling point | 1390 °C | | | 99.9839 °C | 1413 °C | 1429 °C | density | 2.13 g/cm^3 | 2.841 g/cm^3 | 1.11 g/cm^3 | 1 g/cm^3 | 2.16 g/cm^3 | 2.68 g/cm^3 | solubility in water | soluble | | miscible | | soluble | soluble | surface tension | 0.07435 N/m | | | 0.0728 N/m | | | dynamic viscosity | 0.004 Pa s (at 350 °C) | | | 8.9×10^-4 Pa s (at 25 °C) | | | odor | | | | odorless | odorless | |
| sodium hydroxide | duretter | sodium hypochlorite | water | sodium chloride | sodium sulfate | Na2FeO4 molar mass | 39.997 g/mol | 151.9 g/mol | 74.44 g/mol | 18.015 g/mol | 58.44 g/mol | 142.04 g/mol | 165.82 g/mol phase | solid (at STP) | | liquid (at STP) | liquid (at STP) | solid (at STP) | solid (at STP) | melting point | 323 °C | | -6 °C | 0 °C | 801 °C | 884 °C | boiling point | 1390 °C | | | 99.9839 °C | 1413 °C | 1429 °C | density | 2.13 g/cm^3 | 2.841 g/cm^3 | 1.11 g/cm^3 | 1 g/cm^3 | 2.16 g/cm^3 | 2.68 g/cm^3 | solubility in water | soluble | | miscible | | soluble | soluble | surface tension | 0.07435 N/m | | | 0.0728 N/m | | | dynamic viscosity | 0.004 Pa s (at 350 °C) | | | 8.9×10^-4 Pa s (at 25 °C) | | | odor | | | | odorless | odorless | |

Units

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