Input interpretation
ammonium cerium(IV) sulfate hydrate | molar mass
Result
Find the molar mass, M, for ammonium cerium(IV) sulfate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ce(NH_4)_4(SO_4)_4·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ce (cerium) | 1 H (hydrogen) | 18 N (nitrogen) | 4 O (oxygen) | 17 S (sulfur) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ce (cerium) | 1 | 140.116 H (hydrogen) | 18 | 1.008 N (nitrogen) | 4 | 14.007 O (oxygen) | 17 | 15.999 S (sulfur) | 4 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ce (cerium) | 1 | 140.116 | 1 × 140.116 = 140.116 H (hydrogen) | 18 | 1.008 | 18 × 1.008 = 18.144 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 17 | 15.999 | 17 × 15.999 = 271.983 S (sulfur) | 4 | 32.06 | 4 × 32.06 = 128.24 M = 140.116 g/mol + 18.144 g/mol + 56.028 g/mol + 271.983 g/mol + 128.24 g/mol = 614.51 g/mol
Unit conversion
0.6145 kg/mol (kilograms per mole)
Comparisons
≈ 0.85 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 3.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 11 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1×10^-21 grams | 1×10^-24 kg (kilograms) | 615 u (unified atomic mass units) | 615 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 615