Input interpretation
![lead(II) chlorate | molar mass](../image_source/52d0c0853291ff538c10ba255f9ba691.png)
lead(II) chlorate | molar mass
Result
![Find the molar mass, M, for lead(II) chlorate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pb(ClO_3)_2 Use the chemical formula, Pb(ClO_3)_2, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 O (oxygen) | 6 Pb (lead) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 O (oxygen) | 6 | 15.999 Pb (lead) | 1 | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 Pb (lead) | 1 | 207.2 | 1 × 207.2 = 207.2 M = 70.90 g/mol + 95.994 g/mol + 207.2 g/mol = 374.1 g/mol](../image_source/5829c708ef53f43d8fae655d01a18f96.png)
Find the molar mass, M, for lead(II) chlorate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pb(ClO_3)_2 Use the chemical formula, Pb(ClO_3)_2, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 O (oxygen) | 6 Pb (lead) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 O (oxygen) | 6 | 15.999 Pb (lead) | 1 | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 Pb (lead) | 1 | 207.2 | 1 × 207.2 = 207.2 M = 70.90 g/mol + 95.994 g/mol + 207.2 g/mol = 374.1 g/mol
Unit conversion
![0.3741 kg/mol (kilograms per mole)](../image_source/79c52976c68600f500658f9fa4d27764.png)
0.3741 kg/mol (kilograms per mole)
Comparisons
![≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/c5a086d70df24ae554feaa3438061358.png)
≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/d13ee9bed415b547332788031cb4eeff.png)
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/8eed784dbbb7e34fdb86a3b8c81369a9.png)
≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.2×10^-22 grams | 6.2×10^-25 kg (kilograms) | 374 u (unified atomic mass units) | 374 Da (daltons)](../image_source/518aaa57f0e28f60013bda937b4b88d5.png)
Mass of a molecule m from m = M/N_A: | 6.2×10^-22 grams | 6.2×10^-25 kg (kilograms) | 374 u (unified atomic mass units) | 374 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 374](../image_source/eb5a523b90973a575d4c0a54d062f0d8.png)
Relative molecular mass M_r from M_r = M_u/M: | 374