Input interpretation
H_2SO_4 (sulfuric acid) + BaCl_2 (barium chloride) ⟶ HCl (hydrogen chloride) + BaSO_4 (barium sulfate)
Balanced equation
Balance the chemical equation algebraically: H_2SO_4 + BaCl_2 ⟶ HCl + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 BaCl_2 ⟶ c_3 HCl + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Ba and Cl: H: | 2 c_1 = c_3 O: | 4 c_1 = 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 Cl: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2SO_4 + BaCl_2 ⟶ 2 HCl + BaSO_4
Structures
+ ⟶ +
Names
sulfuric acid + barium chloride ⟶ hydrogen chloride + barium sulfate
Reaction thermodynamics
Enthalpy
| sulfuric acid | barium chloride | hydrogen chloride | barium sulfate molecular enthalpy | -814 kJ/mol | -855 kJ/mol | -92.3 kJ/mol | -1473 kJ/mol total enthalpy | -814 kJ/mol | -855 kJ/mol | -184.6 kJ/mol | -1473 kJ/mol | H_initial = -1669 kJ/mol | | H_final = -1658 kJ/mol | ΔH_rxn^0 | -1658 kJ/mol - -1669 kJ/mol = 11.2 kJ/mol (endothermic) | | |
Gibbs free energy
| sulfuric acid | barium chloride | hydrogen chloride | barium sulfate molecular free energy | -690 kJ/mol | -806.7 kJ/mol | -95.3 kJ/mol | -1362 kJ/mol total free energy | -690 kJ/mol | -806.7 kJ/mol | -190.6 kJ/mol | -1362 kJ/mol | G_initial = -1497 kJ/mol | | G_final = -1553 kJ/mol | ΔG_rxn^0 | -1553 kJ/mol - -1497 kJ/mol = -56.1 kJ/mol (exergonic) | | |
Equilibrium constant
Construct the equilibrium constant, K, expression for: H_2SO_4 + BaCl_2 ⟶ HCl + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + BaCl_2 ⟶ 2 HCl + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 BaCl_2 | 1 | -1 HCl | 2 | 2 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) BaCl_2 | 1 | -1 | ([BaCl2])^(-1) HCl | 2 | 2 | ([HCl])^2 BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-1) ([BaCl2])^(-1) ([HCl])^2 [BaSO4] = (([HCl])^2 [BaSO4])/([H2SO4] [BaCl2])
Rate of reaction
Construct the rate of reaction expression for: H_2SO_4 + BaCl_2 ⟶ HCl + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + BaCl_2 ⟶ 2 HCl + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 BaCl_2 | 1 | -1 HCl | 2 | 2 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) BaCl_2 | 1 | -1 | -(Δ[BaCl2])/(Δt) HCl | 2 | 2 | 1/2 (Δ[HCl])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2SO4])/(Δt) = -(Δ[BaCl2])/(Δt) = 1/2 (Δ[HCl])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
| sulfuric acid | barium chloride | hydrogen chloride | barium sulfate formula | H_2SO_4 | BaCl_2 | HCl | BaSO_4 Hill formula | H_2O_4S | BaCl_2 | ClH | BaO_4S name | sulfuric acid | barium chloride | hydrogen chloride | barium sulfate IUPAC name | sulfuric acid | barium(+2) cation dichloride | hydrogen chloride | barium(+2) cation sulfate
Substance properties
| sulfuric acid | barium chloride | hydrogen chloride | barium sulfate molar mass | 98.07 g/mol | 208.2 g/mol | 36.46 g/mol | 233.38 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 10.371 °C | 963 °C | -114.17 °C | 1345 °C boiling point | 279.6 °C | | -85 °C | density | 1.8305 g/cm^3 | 3.856 g/cm^3 | 0.00149 g/cm^3 (at 25 °C) | 4.5 g/cm^3 solubility in water | very soluble | | miscible | insoluble surface tension | 0.0735 N/m | | | dynamic viscosity | 0.021 Pa s (at 25 °C) | | | odor | odorless | odorless | |
Units