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HNO3 + KMnO4 + H2O2 = H2O + O2 + KNO3 + Mn(NO3)2

Input interpretation

nitric acid + potassium permanganate + hydrogen peroxide ⟶ water + oxygen + potassium nitrate + manganese(II) nitrate
nitric acid + potassium permanganate + hydrogen peroxide ⟶ water + oxygen + potassium nitrate + manganese(II) nitrate

Balanced equation

Balance the chemical equation algebraically:  + + ⟶ + + +  Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7  Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, K and Mn: H: | c_1 + 2 c_3 = 2 c_4 N: | c_1 = c_6 + 2 c_7 O: | 3 c_1 + 4 c_2 + 2 c_3 = c_4 + 2 c_5 + 3 c_6 + 6 c_7 K: | c_2 = c_6 Mn: | c_2 = c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_2 = c_1/3 c_3 = 1 c_4 = c_1/2 + 1 c_5 = (5 c_1)/12 + 1/2 c_6 = c_1/3 c_7 = c_1/3 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 6 and solve for the remaining coefficients: c_1 = 6 c_2 = 2 c_3 = 1 c_4 = 4 c_5 = 3 c_6 = 2 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 6 + 2 + ⟶ 4 + 3 + 2 + 2
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, K and Mn: H: | c_1 + 2 c_3 = 2 c_4 N: | c_1 = c_6 + 2 c_7 O: | 3 c_1 + 4 c_2 + 2 c_3 = c_4 + 2 c_5 + 3 c_6 + 6 c_7 K: | c_2 = c_6 Mn: | c_2 = c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_2 = c_1/3 c_3 = 1 c_4 = c_1/2 + 1 c_5 = (5 c_1)/12 + 1/2 c_6 = c_1/3 c_7 = c_1/3 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 6 and solve for the remaining coefficients: c_1 = 6 c_2 = 2 c_3 = 1 c_4 = 4 c_5 = 3 c_6 = 2 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + 2 + ⟶ 4 + 3 + 2 + 2

Structures

 + + ⟶ + + +
+ + ⟶ + + +

Names

nitric acid + potassium permanganate + hydrogen peroxide ⟶ water + oxygen + potassium nitrate + manganese(II) nitrate
nitric acid + potassium permanganate + hydrogen peroxide ⟶ water + oxygen + potassium nitrate + manganese(II) nitrate

Chemical names and formulas

 | nitric acid | potassium permanganate | hydrogen peroxide | water | oxygen | potassium nitrate | manganese(II) nitrate Hill formula | HNO_3 | KMnO_4 | H_2O_2 | H_2O | O_2 | KNO_3 | MnN_2O_6 name | nitric acid | potassium permanganate | hydrogen peroxide | water | oxygen | potassium nitrate | manganese(II) nitrate IUPAC name | nitric acid | potassium permanganate | hydrogen peroxide | water | molecular oxygen | potassium nitrate | manganese(2+) dinitrate
| nitric acid | potassium permanganate | hydrogen peroxide | water | oxygen | potassium nitrate | manganese(II) nitrate Hill formula | HNO_3 | KMnO_4 | H_2O_2 | H_2O | O_2 | KNO_3 | MnN_2O_6 name | nitric acid | potassium permanganate | hydrogen peroxide | water | oxygen | potassium nitrate | manganese(II) nitrate IUPAC name | nitric acid | potassium permanganate | hydrogen peroxide | water | molecular oxygen | potassium nitrate | manganese(2+) dinitrate