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molar mass of 3-methyl-2-thienylzinc bromide

Input interpretation

3-methyl-2-thienylzinc bromide | molar mass
3-methyl-2-thienylzinc bromide | molar mass

Result

Find the molar mass, M, for 3-methyl-2-thienylzinc bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_5H_5BrSZn Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Br (bromine) | 1  C (carbon) | 5  H (hydrogen) | 5  S (sulfur) | 1  Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Br (bromine) | 1 | 79.904  C (carbon) | 5 | 12.011  H (hydrogen) | 5 | 1.008  S (sulfur) | 1 | 32.06  Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904  C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055  H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040  S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06  Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38  M = 79.904 g/mol + 60.055 g/mol + 5.040 g/mol + 32.06 g/mol + 65.38 g/mol = 242.44 g/mol
Find the molar mass, M, for 3-methyl-2-thienylzinc bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_5H_5BrSZn Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 5 H (hydrogen) | 5 S (sulfur) | 1 Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 5 | 12.011 H (hydrogen) | 5 | 1.008 S (sulfur) | 1 | 32.06 Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 M = 79.904 g/mol + 60.055 g/mol + 5.040 g/mol + 32.06 g/mol + 65.38 g/mol = 242.44 g/mol

Unit conversion

0.2424 kg/mol (kilograms per mole)
0.2424 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 4×10^-22 grams  | 4×10^-25 kg (kilograms)  | 242 u (unified atomic mass units)  | 242 Da (daltons)
Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 242 u (unified atomic mass units) | 242 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 242
Relative molecular mass M_r from M_r = M_u/M: | 242