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NaOH + Fe2O3 = Fe(OH)3 + Na2O

Input interpretation

NaOH sodium hydroxide + Fe_2O_3 iron(III) oxide ⟶ Fe(OH)_3 iron(III) hydroxide + Na_2O sodium oxide
NaOH sodium hydroxide + Fe_2O_3 iron(III) oxide ⟶ Fe(OH)_3 iron(III) hydroxide + Na_2O sodium oxide

Balanced equation

Balance the chemical equation algebraically: NaOH + Fe_2O_3 ⟶ Fe(OH)_3 + Na_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 Fe_2O_3 ⟶ c_3 Fe(OH)_3 + c_4 Na_2O Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and Fe: H: | c_1 = 3 c_3 Na: | c_1 = 2 c_4 O: | c_1 + 3 c_2 = 3 c_3 + c_4 Fe: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 2 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 6 NaOH + Fe_2O_3 ⟶ 2 Fe(OH)_3 + 3 Na_2O
Balance the chemical equation algebraically: NaOH + Fe_2O_3 ⟶ Fe(OH)_3 + Na_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 Fe_2O_3 ⟶ c_3 Fe(OH)_3 + c_4 Na_2O Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and Fe: H: | c_1 = 3 c_3 Na: | c_1 = 2 c_4 O: | c_1 + 3 c_2 = 3 c_3 + c_4 Fe: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 2 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 NaOH + Fe_2O_3 ⟶ 2 Fe(OH)_3 + 3 Na_2O

Structures

 + ⟶ +
+ ⟶ +

Names

sodium hydroxide + iron(III) oxide ⟶ iron(III) hydroxide + sodium oxide
sodium hydroxide + iron(III) oxide ⟶ iron(III) hydroxide + sodium oxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: NaOH + Fe_2O_3 ⟶ Fe(OH)_3 + Na_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 NaOH + Fe_2O_3 ⟶ 2 Fe(OH)_3 + 3 Na_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 6 | -6 Fe_2O_3 | 1 | -1 Fe(OH)_3 | 2 | 2 Na_2O | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 6 | -6 | ([NaOH])^(-6) Fe_2O_3 | 1 | -1 | ([Fe2O3])^(-1) Fe(OH)_3 | 2 | 2 | ([Fe(OH)3])^2 Na_2O | 3 | 3 | ([Na2O])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([NaOH])^(-6) ([Fe2O3])^(-1) ([Fe(OH)3])^2 ([Na2O])^3 = (([Fe(OH)3])^2 ([Na2O])^3)/(([NaOH])^6 [Fe2O3])
Construct the equilibrium constant, K, expression for: NaOH + Fe_2O_3 ⟶ Fe(OH)_3 + Na_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 NaOH + Fe_2O_3 ⟶ 2 Fe(OH)_3 + 3 Na_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 6 | -6 Fe_2O_3 | 1 | -1 Fe(OH)_3 | 2 | 2 Na_2O | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 6 | -6 | ([NaOH])^(-6) Fe_2O_3 | 1 | -1 | ([Fe2O3])^(-1) Fe(OH)_3 | 2 | 2 | ([Fe(OH)3])^2 Na_2O | 3 | 3 | ([Na2O])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-6) ([Fe2O3])^(-1) ([Fe(OH)3])^2 ([Na2O])^3 = (([Fe(OH)3])^2 ([Na2O])^3)/(([NaOH])^6 [Fe2O3])

Rate of reaction

Construct the rate of reaction expression for: NaOH + Fe_2O_3 ⟶ Fe(OH)_3 + Na_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 NaOH + Fe_2O_3 ⟶ 2 Fe(OH)_3 + 3 Na_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 6 | -6 Fe_2O_3 | 1 | -1 Fe(OH)_3 | 2 | 2 Na_2O | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 6 | -6 | -1/6 (Δ[NaOH])/(Δt) Fe_2O_3 | 1 | -1 | -(Δ[Fe2O3])/(Δt) Fe(OH)_3 | 2 | 2 | 1/2 (Δ[Fe(OH)3])/(Δt) Na_2O | 3 | 3 | 1/3 (Δ[Na2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/6 (Δ[NaOH])/(Δt) = -(Δ[Fe2O3])/(Δt) = 1/2 (Δ[Fe(OH)3])/(Δt) = 1/3 (Δ[Na2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NaOH + Fe_2O_3 ⟶ Fe(OH)_3 + Na_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 NaOH + Fe_2O_3 ⟶ 2 Fe(OH)_3 + 3 Na_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 6 | -6 Fe_2O_3 | 1 | -1 Fe(OH)_3 | 2 | 2 Na_2O | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 6 | -6 | -1/6 (Δ[NaOH])/(Δt) Fe_2O_3 | 1 | -1 | -(Δ[Fe2O3])/(Δt) Fe(OH)_3 | 2 | 2 | 1/2 (Δ[Fe(OH)3])/(Δt) Na_2O | 3 | 3 | 1/3 (Δ[Na2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[NaOH])/(Δt) = -(Δ[Fe2O3])/(Δt) = 1/2 (Δ[Fe(OH)3])/(Δt) = 1/3 (Δ[Na2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | sodium hydroxide | iron(III) oxide | iron(III) hydroxide | sodium oxide formula | NaOH | Fe_2O_3 | Fe(OH)_3 | Na_2O Hill formula | HNaO | Fe_2O_3 | FeH_3O_3 | Na_2O name | sodium hydroxide | iron(III) oxide | iron(III) hydroxide | sodium oxide IUPAC name | sodium hydroxide | | ferric trihydroxide | disodium oxygen(-2) anion
| sodium hydroxide | iron(III) oxide | iron(III) hydroxide | sodium oxide formula | NaOH | Fe_2O_3 | Fe(OH)_3 | Na_2O Hill formula | HNaO | Fe_2O_3 | FeH_3O_3 | Na_2O name | sodium hydroxide | iron(III) oxide | iron(III) hydroxide | sodium oxide IUPAC name | sodium hydroxide | | ferric trihydroxide | disodium oxygen(-2) anion

Substance properties

 | sodium hydroxide | iron(III) oxide | iron(III) hydroxide | sodium oxide molar mass | 39.997 g/mol | 159.69 g/mol | 106.87 g/mol | 61.979 g/mol phase | solid (at STP) | solid (at STP) | |  melting point | 323 °C | 1565 °C | |  boiling point | 1390 °C | | |  density | 2.13 g/cm^3 | 5.26 g/cm^3 | | 2.27 g/cm^3 solubility in water | soluble | insoluble | |  surface tension | 0.07435 N/m | | |  dynamic viscosity | 0.004 Pa s (at 350 °C) | | |  odor | | odorless | |
| sodium hydroxide | iron(III) oxide | iron(III) hydroxide | sodium oxide molar mass | 39.997 g/mol | 159.69 g/mol | 106.87 g/mol | 61.979 g/mol phase | solid (at STP) | solid (at STP) | | melting point | 323 °C | 1565 °C | | boiling point | 1390 °C | | | density | 2.13 g/cm^3 | 5.26 g/cm^3 | | 2.27 g/cm^3 solubility in water | soluble | insoluble | | surface tension | 0.07435 N/m | | | dynamic viscosity | 0.004 Pa s (at 350 °C) | | | odor | | odorless | |

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