Input interpretation
![ammonium hexachloroiridate(IV) | molar mass](../image_source/41c1f3aae32ced5adb4f9b8176a08326.png)
ammonium hexachloroiridate(IV) | molar mass
Result
![Find the molar mass, M, for ammonium hexachloroiridate(IV): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (NH_4)_2IrCl_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 6 H (hydrogen) | 8 Ir (iridium) | 1 N (nitrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 6 | 35.45 H (hydrogen) | 8 | 1.008 Ir (iridium) | 1 | 192.217 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 6 | 35.45 | 6 × 35.45 = 212.70 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 Ir (iridium) | 1 | 192.217 | 1 × 192.217 = 192.217 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M = 212.70 g/mol + 8.064 g/mol + 192.217 g/mol + 28.014 g/mol = 441.00 g/mol](../image_source/eefc2eb48ed796dfaa5ce0c8aa956eb9.png)
Find the molar mass, M, for ammonium hexachloroiridate(IV): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (NH_4)_2IrCl_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 6 H (hydrogen) | 8 Ir (iridium) | 1 N (nitrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 6 | 35.45 H (hydrogen) | 8 | 1.008 Ir (iridium) | 1 | 192.217 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 6 | 35.45 | 6 × 35.45 = 212.70 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 Ir (iridium) | 1 | 192.217 | 1 × 192.217 = 192.217 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M = 212.70 g/mol + 8.064 g/mol + 192.217 g/mol + 28.014 g/mol = 441.00 g/mol
Unit conversion
![0.441 kg/mol (kilograms per mole)](../image_source/6f613dfcb1852003e83da32caf7e4e7d.png)
0.441 kg/mol (kilograms per mole)
Comparisons
![≈ 0.61 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/7b2cf4f9475f7b2e252d470317d51eed.png)
≈ 0.61 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/d3144bf6817ad87eae8226235ac747ac.png)
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/150f8f3bd9f10becd7ae7b8512b05092.png)
≈ 7.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.3×10^-22 grams | 7.3×10^-25 kg (kilograms) | 441 u (unified atomic mass units) | 441 Da (daltons)](../image_source/7b59ef8b23d201e7da7d85cf362a0814.png)
Mass of a molecule m from m = M/N_A: | 7.3×10^-22 grams | 7.3×10^-25 kg (kilograms) | 441 u (unified atomic mass units) | 441 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 441](../image_source/280bec60fd72a76ca35ae2fcfd3eb358.png)
Relative molecular mass M_r from M_r = M_u/M: | 441