Input interpretation
3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 11, 11, 12, 12, 12-heneicosafluorododecyl acrylate | molar mass
Result
Find the molar mass, M, for 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 11, 11, 12, 12, 12-heneicosafluorododecyl acrylate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=CHCO_2CH_2CH_2(CF_2)_9CF_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 15 F (fluorine) | 21 H (hydrogen) | 7 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 15 | 12.011 F (fluorine) | 21 | 18.998403163 H (hydrogen) | 7 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 15 | 12.011 | 15 × 12.011 = 180.165 F (fluorine) | 21 | 18.998403163 | 21 × 18.998403163 = 398.966466423 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 180.165 g/mol + 398.966466423 g/mol + 7.056 g/mol + 31.998 g/mol = 618.185 g/mol
Unit conversion
0.61819 kg/mol (kilograms per mole)
Comparisons
≈ 0.86 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 3.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 11 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1×10^-21 grams | 1×10^-24 kg (kilograms) | 618 u (unified atomic mass units) | 618 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 618