Input interpretation
![HClO_4 perchloric acid + Fe(OH)_2 iron(II) hydroxide ⟶ H_2O water + O_8Cl_2Fe_1 iron(II) perchlorate](../image_source/4b2c659baee2e80e744c5d99e49fb05a.png)
HClO_4 perchloric acid + Fe(OH)_2 iron(II) hydroxide ⟶ H_2O water + O_8Cl_2Fe_1 iron(II) perchlorate
Balanced equation
![Balance the chemical equation algebraically: HClO_4 + Fe(OH)_2 ⟶ H_2O + O_8Cl_2Fe_1 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HClO_4 + c_2 Fe(OH)_2 ⟶ c_3 H_2O + c_4 O_8Cl_2Fe_1 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, O and Fe: Cl: | c_1 = 2 c_4 H: | c_1 + 2 c_2 = 2 c_3 O: | 4 c_1 + 2 c_2 = c_3 + 8 c_4 Fe: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HClO_4 + Fe(OH)_2 ⟶ 2 H_2O + O_8Cl_2Fe_1](../image_source/c201c35e8234a6e1f96ec7baac7853d4.png)
Balance the chemical equation algebraically: HClO_4 + Fe(OH)_2 ⟶ H_2O + O_8Cl_2Fe_1 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HClO_4 + c_2 Fe(OH)_2 ⟶ c_3 H_2O + c_4 O_8Cl_2Fe_1 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, O and Fe: Cl: | c_1 = 2 c_4 H: | c_1 + 2 c_2 = 2 c_3 O: | 4 c_1 + 2 c_2 = c_3 + 8 c_4 Fe: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HClO_4 + Fe(OH)_2 ⟶ 2 H_2O + O_8Cl_2Fe_1
Structures
![+ ⟶ +](../image_source/e57b0550b527ba80d9462f33e1712b53.png)
+ ⟶ +
Names
![perchloric acid + iron(II) hydroxide ⟶ water + iron(II) perchlorate](../image_source/9e7ed28582a05a820f3772c5f5e7c811.png)
perchloric acid + iron(II) hydroxide ⟶ water + iron(II) perchlorate
Equilibrium constant
![Construct the equilibrium constant, K, expression for: HClO_4 + Fe(OH)_2 ⟶ H_2O + O_8Cl_2Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HClO_4 + Fe(OH)_2 ⟶ 2 H_2O + O_8Cl_2Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HClO_4 | 2 | -2 Fe(OH)_2 | 1 | -1 H_2O | 2 | 2 O_8Cl_2Fe_1 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HClO_4 | 2 | -2 | ([HClO4])^(-2) Fe(OH)_2 | 1 | -1 | ([Fe(OH)2])^(-1) H_2O | 2 | 2 | ([H2O])^2 O_8Cl_2Fe_1 | 1 | 1 | [O8Cl2Fe1] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HClO4])^(-2) ([Fe(OH)2])^(-1) ([H2O])^2 [O8Cl2Fe1] = (([H2O])^2 [O8Cl2Fe1])/(([HClO4])^2 [Fe(OH)2])](../image_source/40f6e6716914bea2f5f14a5877c0d786.png)
Construct the equilibrium constant, K, expression for: HClO_4 + Fe(OH)_2 ⟶ H_2O + O_8Cl_2Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HClO_4 + Fe(OH)_2 ⟶ 2 H_2O + O_8Cl_2Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HClO_4 | 2 | -2 Fe(OH)_2 | 1 | -1 H_2O | 2 | 2 O_8Cl_2Fe_1 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HClO_4 | 2 | -2 | ([HClO4])^(-2) Fe(OH)_2 | 1 | -1 | ([Fe(OH)2])^(-1) H_2O | 2 | 2 | ([H2O])^2 O_8Cl_2Fe_1 | 1 | 1 | [O8Cl2Fe1] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HClO4])^(-2) ([Fe(OH)2])^(-1) ([H2O])^2 [O8Cl2Fe1] = (([H2O])^2 [O8Cl2Fe1])/(([HClO4])^2 [Fe(OH)2])
Rate of reaction
![Construct the rate of reaction expression for: HClO_4 + Fe(OH)_2 ⟶ H_2O + O_8Cl_2Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HClO_4 + Fe(OH)_2 ⟶ 2 H_2O + O_8Cl_2Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HClO_4 | 2 | -2 Fe(OH)_2 | 1 | -1 H_2O | 2 | 2 O_8Cl_2Fe_1 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HClO_4 | 2 | -2 | -1/2 (Δ[HClO4])/(Δt) Fe(OH)_2 | 1 | -1 | -(Δ[Fe(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) O_8Cl_2Fe_1 | 1 | 1 | (Δ[O8Cl2Fe1])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[HClO4])/(Δt) = -(Δ[Fe(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[O8Cl2Fe1])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/ced4a980baecdbee7e0081facdd83328.png)
Construct the rate of reaction expression for: HClO_4 + Fe(OH)_2 ⟶ H_2O + O_8Cl_2Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HClO_4 + Fe(OH)_2 ⟶ 2 H_2O + O_8Cl_2Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HClO_4 | 2 | -2 Fe(OH)_2 | 1 | -1 H_2O | 2 | 2 O_8Cl_2Fe_1 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HClO_4 | 2 | -2 | -1/2 (Δ[HClO4])/(Δt) Fe(OH)_2 | 1 | -1 | -(Δ[Fe(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) O_8Cl_2Fe_1 | 1 | 1 | (Δ[O8Cl2Fe1])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[HClO4])/(Δt) = -(Δ[Fe(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[O8Cl2Fe1])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| perchloric acid | iron(II) hydroxide | water | iron(II) perchlorate formula | HClO_4 | Fe(OH)_2 | H_2O | O_8Cl_2Fe_1 Hill formula | ClHO_4 | FeH_2O_2 | H_2O | Cl_2FeO_8 name | perchloric acid | iron(II) hydroxide | water | iron(II) perchlorate IUPAC name | perchloric acid | ferrous dihydroxide | water | iron(2+) diperchlorate](../image_source/055c53cdadbfd10ebb372e731a4fbbd6.png)
| perchloric acid | iron(II) hydroxide | water | iron(II) perchlorate formula | HClO_4 | Fe(OH)_2 | H_2O | O_8Cl_2Fe_1 Hill formula | ClHO_4 | FeH_2O_2 | H_2O | Cl_2FeO_8 name | perchloric acid | iron(II) hydroxide | water | iron(II) perchlorate IUPAC name | perchloric acid | ferrous dihydroxide | water | iron(2+) diperchlorate
Substance properties
![| perchloric acid | iron(II) hydroxide | water | iron(II) perchlorate molar mass | 100.5 g/mol | 89.86 g/mol | 18.015 g/mol | 254.7 g/mol phase | liquid (at STP) | | liquid (at STP) | melting point | -112 °C | | 0 °C | boiling point | 90 °C | | 99.9839 °C | density | 1.77 g/cm^3 | | 1 g/cm^3 | solubility in water | very soluble | | | surface tension | | | 0.0728 N/m | dynamic viscosity | 8×10^-4 Pa s (at 25 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | odorless | | odorless |](../image_source/94c120cafd9e729c986a07939644ce8e.png)
| perchloric acid | iron(II) hydroxide | water | iron(II) perchlorate molar mass | 100.5 g/mol | 89.86 g/mol | 18.015 g/mol | 254.7 g/mol phase | liquid (at STP) | | liquid (at STP) | melting point | -112 °C | | 0 °C | boiling point | 90 °C | | 99.9839 °C | density | 1.77 g/cm^3 | | 1 g/cm^3 | solubility in water | very soluble | | | surface tension | | | 0.0728 N/m | dynamic viscosity | 8×10^-4 Pa s (at 25 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | odorless | | odorless |
Units