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KOH + KClO3 + KCrO2 = H2O + KCl + K2CrO4

Input interpretation

KOH potassium hydroxide + KClO_3 potassium chlorate + KCrO2 ⟶ H_2O water + KCl potassium chloride + K_2CrO_4 potassium chromate
KOH potassium hydroxide + KClO_3 potassium chlorate + KCrO2 ⟶ H_2O water + KCl potassium chloride + K_2CrO_4 potassium chromate

Balanced equation

Balance the chemical equation algebraically: KOH + KClO_3 + KCrO2 ⟶ H_2O + KCl + K_2CrO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 KClO_3 + c_3 KCrO2 ⟶ c_4 H_2O + c_5 KCl + c_6 K_2CrO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Cr: H: | c_1 = 2 c_4 K: | c_1 + c_2 + c_3 = c_5 + 2 c_6 O: | c_1 + 3 c_2 + 2 c_3 = c_4 + 4 c_6 Cl: | c_2 = c_5 Cr: | c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 c_5 = 1 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 KOH + KClO_3 + 2 KCrO2 ⟶ H_2O + KCl + 2 K_2CrO_4
Balance the chemical equation algebraically: KOH + KClO_3 + KCrO2 ⟶ H_2O + KCl + K_2CrO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 KClO_3 + c_3 KCrO2 ⟶ c_4 H_2O + c_5 KCl + c_6 K_2CrO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Cr: H: | c_1 = 2 c_4 K: | c_1 + c_2 + c_3 = c_5 + 2 c_6 O: | c_1 + 3 c_2 + 2 c_3 = c_4 + 4 c_6 Cl: | c_2 = c_5 Cr: | c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 c_5 = 1 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 KOH + KClO_3 + 2 KCrO2 ⟶ H_2O + KCl + 2 K_2CrO_4

Structures

 + + KCrO2 ⟶ + +
+ + KCrO2 ⟶ + +

Names

potassium hydroxide + potassium chlorate + KCrO2 ⟶ water + potassium chloride + potassium chromate
potassium hydroxide + potassium chlorate + KCrO2 ⟶ water + potassium chloride + potassium chromate

Equilibrium constant

Construct the equilibrium constant, K, expression for: KOH + KClO_3 + KCrO2 ⟶ H_2O + KCl + K_2CrO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 KOH + KClO_3 + 2 KCrO2 ⟶ H_2O + KCl + 2 K_2CrO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 KClO_3 | 1 | -1 KCrO2 | 2 | -2 H_2O | 1 | 1 KCl | 1 | 1 K_2CrO_4 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 2 | -2 | ([KOH])^(-2) KClO_3 | 1 | -1 | ([KClO3])^(-1) KCrO2 | 2 | -2 | ([KCrO2])^(-2) H_2O | 1 | 1 | [H2O] KCl | 1 | 1 | [KCl] K_2CrO_4 | 2 | 2 | ([K2CrO4])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([KOH])^(-2) ([KClO3])^(-1) ([KCrO2])^(-2) [H2O] [KCl] ([K2CrO4])^2 = ([H2O] [KCl] ([K2CrO4])^2)/(([KOH])^2 [KClO3] ([KCrO2])^2)
Construct the equilibrium constant, K, expression for: KOH + KClO_3 + KCrO2 ⟶ H_2O + KCl + K_2CrO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 KOH + KClO_3 + 2 KCrO2 ⟶ H_2O + KCl + 2 K_2CrO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 KClO_3 | 1 | -1 KCrO2 | 2 | -2 H_2O | 1 | 1 KCl | 1 | 1 K_2CrO_4 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 2 | -2 | ([KOH])^(-2) KClO_3 | 1 | -1 | ([KClO3])^(-1) KCrO2 | 2 | -2 | ([KCrO2])^(-2) H_2O | 1 | 1 | [H2O] KCl | 1 | 1 | [KCl] K_2CrO_4 | 2 | 2 | ([K2CrO4])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-2) ([KClO3])^(-1) ([KCrO2])^(-2) [H2O] [KCl] ([K2CrO4])^2 = ([H2O] [KCl] ([K2CrO4])^2)/(([KOH])^2 [KClO3] ([KCrO2])^2)

Rate of reaction

Construct the rate of reaction expression for: KOH + KClO_3 + KCrO2 ⟶ H_2O + KCl + K_2CrO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 KOH + KClO_3 + 2 KCrO2 ⟶ H_2O + KCl + 2 K_2CrO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 KClO_3 | 1 | -1 KCrO2 | 2 | -2 H_2O | 1 | 1 KCl | 1 | 1 K_2CrO_4 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 2 | -2 | -1/2 (Δ[KOH])/(Δt) KClO_3 | 1 | -1 | -(Δ[KClO3])/(Δt) KCrO2 | 2 | -2 | -1/2 (Δ[KCrO2])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) KCl | 1 | 1 | (Δ[KCl])/(Δt) K_2CrO_4 | 2 | 2 | 1/2 (Δ[K2CrO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[KOH])/(Δt) = -(Δ[KClO3])/(Δt) = -1/2 (Δ[KCrO2])/(Δt) = (Δ[H2O])/(Δt) = (Δ[KCl])/(Δt) = 1/2 (Δ[K2CrO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: KOH + KClO_3 + KCrO2 ⟶ H_2O + KCl + K_2CrO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 KOH + KClO_3 + 2 KCrO2 ⟶ H_2O + KCl + 2 K_2CrO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 KClO_3 | 1 | -1 KCrO2 | 2 | -2 H_2O | 1 | 1 KCl | 1 | 1 K_2CrO_4 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 2 | -2 | -1/2 (Δ[KOH])/(Δt) KClO_3 | 1 | -1 | -(Δ[KClO3])/(Δt) KCrO2 | 2 | -2 | -1/2 (Δ[KCrO2])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) KCl | 1 | 1 | (Δ[KCl])/(Δt) K_2CrO_4 | 2 | 2 | 1/2 (Δ[K2CrO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[KOH])/(Δt) = -(Δ[KClO3])/(Δt) = -1/2 (Δ[KCrO2])/(Δt) = (Δ[H2O])/(Δt) = (Δ[KCl])/(Δt) = 1/2 (Δ[K2CrO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | potassium hydroxide | potassium chlorate | KCrO2 | water | potassium chloride | potassium chromate formula | KOH | KClO_3 | KCrO2 | H_2O | KCl | K_2CrO_4 Hill formula | HKO | ClKO_3 | CrKO2 | H_2O | ClK | CrK_2O_4 name | potassium hydroxide | potassium chlorate | | water | potassium chloride | potassium chromate IUPAC name | potassium hydroxide | potassium chlorate | | water | potassium chloride | dipotassium dioxido-dioxochromium
| potassium hydroxide | potassium chlorate | KCrO2 | water | potassium chloride | potassium chromate formula | KOH | KClO_3 | KCrO2 | H_2O | KCl | K_2CrO_4 Hill formula | HKO | ClKO_3 | CrKO2 | H_2O | ClK | CrK_2O_4 name | potassium hydroxide | potassium chlorate | | water | potassium chloride | potassium chromate IUPAC name | potassium hydroxide | potassium chlorate | | water | potassium chloride | dipotassium dioxido-dioxochromium

Substance properties

 | potassium hydroxide | potassium chlorate | KCrO2 | water | potassium chloride | potassium chromate molar mass | 56.105 g/mol | 122.5 g/mol | 123.09 g/mol | 18.015 g/mol | 74.55 g/mol | 194.19 g/mol phase | solid (at STP) | solid (at STP) | | liquid (at STP) | solid (at STP) | solid (at STP) melting point | 406 °C | 356 °C | | 0 °C | 770 °C | 971 °C boiling point | 1327 °C | | | 99.9839 °C | 1420 °C |  density | 2.044 g/cm^3 | 2.34 g/cm^3 | | 1 g/cm^3 | 1.98 g/cm^3 | 2.73 g/cm^3 solubility in water | soluble | soluble | | | soluble | soluble surface tension | | | | 0.0728 N/m | |  dynamic viscosity | 0.001 Pa s (at 550 °C) | | | 8.9×10^-4 Pa s (at 25 °C) | |  odor | | | | odorless | odorless | odorless
| potassium hydroxide | potassium chlorate | KCrO2 | water | potassium chloride | potassium chromate molar mass | 56.105 g/mol | 122.5 g/mol | 123.09 g/mol | 18.015 g/mol | 74.55 g/mol | 194.19 g/mol phase | solid (at STP) | solid (at STP) | | liquid (at STP) | solid (at STP) | solid (at STP) melting point | 406 °C | 356 °C | | 0 °C | 770 °C | 971 °C boiling point | 1327 °C | | | 99.9839 °C | 1420 °C | density | 2.044 g/cm^3 | 2.34 g/cm^3 | | 1 g/cm^3 | 1.98 g/cm^3 | 2.73 g/cm^3 solubility in water | soluble | soluble | | | soluble | soluble surface tension | | | | 0.0728 N/m | | dynamic viscosity | 0.001 Pa s (at 550 °C) | | | 8.9×10^-4 Pa s (at 25 °C) | | odor | | | | odorless | odorless | odorless

Units