Input interpretation
![pentabromophenol | molar mass](../image_source/3166bd428bb9d4123940601f7599b996.png)
pentabromophenol | molar mass
Result
![Find the molar mass, M, for pentabromophenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6Br_5OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 5 C (carbon) | 6 H (hydrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 5 | 79.904 C (carbon) | 6 | 12.011 H (hydrogen) | 1 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 5 | 79.904 | 5 × 79.904 = 399.520 C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 399.520 g/mol + 72.066 g/mol + 1.008 g/mol + 15.999 g/mol = 488.593 g/mol](../image_source/539a32d2a26bab7ab5793052e095d848.png)
Find the molar mass, M, for pentabromophenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6Br_5OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 5 C (carbon) | 6 H (hydrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 5 | 79.904 C (carbon) | 6 | 12.011 H (hydrogen) | 1 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 5 | 79.904 | 5 × 79.904 = 399.520 C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 399.520 g/mol + 72.066 g/mol + 1.008 g/mol + 15.999 g/mol = 488.593 g/mol
Unit conversion
![0.48859 kg/mol (kilograms per mole)](../image_source/14e26bc53fc1321ad52ed5a1c42cd6b6.png)
0.48859 kg/mol (kilograms per mole)
Comparisons
![≈ 0.68 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/2a1ddb02d1aa08c8d87e592ddf715973.png)
≈ 0.68 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/5279125f39f6c0a67e24ec94ac0bfe9f.png)
≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 8.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/c1f83b274b8b0dc99eadfa206ccbbf73.png)
≈ 8.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 8.1×10^-22 grams | 8.1×10^-25 kg (kilograms) | 489 u (unified atomic mass units) | 489 Da (daltons)](../image_source/96ff8575b43408d439b6bb383e91b65b.png)
Mass of a molecule m from m = M/N_A: | 8.1×10^-22 grams | 8.1×10^-25 kg (kilograms) | 489 u (unified atomic mass units) | 489 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 489](../image_source/159c5c92ddfe09a76ef7e52200791684.png)
Relative molecular mass M_r from M_r = M_u/M: | 489