Input interpretation
lutetium(III) iodide | molar mass
Result
Find the molar mass, M, for lutetium(III) iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: I_3Lu Use the chemical formula to count the number of atoms, N_i, for each element: | N_i I (iodine) | 3 Lu (lutetium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) I (iodine) | 3 | 126.90447 Lu (lutetium) | 1 | 174.9668 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) I (iodine) | 3 | 126.90447 | 3 × 126.90447 = 380.71341 Lu (lutetium) | 1 | 174.9668 | 1 × 174.9668 = 174.9668 M = 380.71341 g/mol + 174.9668 g/mol = 555.6802 g/mol
Unit conversion
0.5556802 kg/mol (kilograms per mole)
Comparisons
≈ 0.77 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 9.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 9.2×10^-22 grams | 9.2×10^-25 kg (kilograms) | 556 u (unified atomic mass units) | 556 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 556