H2S + HClO3 = H2O + HCl + S

hydrogen sulfide + HClO3 ⟶ water + hydrogen chloride + mixed sulfur

Balance the chemical equation algebraically: + HClO3 ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 HClO3 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, S, Cl and O: H: | 2 c_1 + c_2 = 2 c_3 + c_4 S: | c_1 = c_5 Cl: | c_2 = c_4 O: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 c_5 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 + HClO3 ⟶ 3 + + 3

+ HClO3 ⟶ + +

hydrogen sulfide + HClO3 ⟶ water + hydrogen chloride + mixed sulfur

| hydrogen sulfide | HClO3 | water | hydrogen chloride | mixed sulfur formula | | HClO3 | | | Hill formula | H_2S | HClO3 | H_2O | ClH | S name | hydrogen sulfide | | water | hydrogen chloride | mixed sulfur IUPAC name | hydrogen sulfide | | water | hydrogen chloride | sulfur