Input interpretation
![cobalt(II) chloride hexahydrate | molar mass](../image_source/51827a2be8484f81e3787c3d13594b6a.png)
cobalt(II) chloride hexahydrate | molar mass
Result
![Find the molar mass, M, for cobalt(II) chloride hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cl_2CoH_12O_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 Co (cobalt) | 1 H (hydrogen) | 12 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 Co (cobalt) | 1 | 58.933194 H (hydrogen) | 12 | 1.008 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 Co (cobalt) | 1 | 58.933194 | 1 × 58.933194 = 58.933194 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 70.90 g/mol + 58.933194 g/mol + 12.096 g/mol + 95.994 g/mol = 237.92 g/mol](../image_source/af495c6b6d7939f9dc332fe6f344c3dd.png)
Find the molar mass, M, for cobalt(II) chloride hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cl_2CoH_12O_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 Co (cobalt) | 1 H (hydrogen) | 12 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 Co (cobalt) | 1 | 58.933194 H (hydrogen) | 12 | 1.008 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 Co (cobalt) | 1 | 58.933194 | 1 × 58.933194 = 58.933194 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 70.90 g/mol + 58.933194 g/mol + 12.096 g/mol + 95.994 g/mol = 237.92 g/mol
Unit conversion
![0.2379 kg/mol (kilograms per mole)](../image_source/53dc067ef960d64844a5daa86229ca97.png)
0.2379 kg/mol (kilograms per mole)
Comparisons
![≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/4e77a45a54b70cc98bc8509600b8ea59.png)
≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/7ef242a2091db96241e4eca45d95d50f.png)
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/18d15143a9920980288ac510e5138244.png)
≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 238 u (unified atomic mass units) | 238 Da (daltons)](../image_source/43267bb73f7ea2bcd2b120e7c653850a.png)
Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 238 u (unified atomic mass units) | 238 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 238](../image_source/5cc03e16625fa1e07f4e4568cfc26d9f.png)
Relative molecular mass M_r from M_r = M_u/M: | 238