KI + Pb(NO3)2 = KNO3 + PbI2

potassium iodide + lead(II) nitrate ⟶ potassium nitrate + lead iodide

Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for I, K, N, O and Pb: I: | c_1 = 2 c_4 K: | c_1 = c_3 N: | 2 c_2 = c_3 O: | 6 c_2 = 3 c_3 Pb: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + ⟶ 2 +

+ ⟶ +

potassium iodide + lead(II) nitrate ⟶ potassium nitrate + lead iodide

| potassium iodide | lead(II) nitrate | potassium nitrate | lead iodide molecular enthalpy | -327.9 kJ/mol | -451.9 kJ/mol | -494.6 kJ/mol | -175.5 kJ/mol total enthalpy | -655.8 kJ/mol | -451.9 kJ/mol | -989.2 kJ/mol | -175.5 kJ/mol | H_initial = -1108 kJ/mol | | H_final = -1165 kJ/mol | ΔH_rxn^0 | -1165 kJ/mol - -1108 kJ/mol = -57 kJ/mol (exothermic) | | |

| potassium iodide | lead(II) nitrate | potassium nitrate | lead iodide Hill formula | IK | N_2O_6Pb | KNO_3 | I_2Pb name | potassium iodide | lead(II) nitrate | potassium nitrate | lead iodide IUPAC name | potassium iodide | plumbous dinitrate | potassium nitrate |

| potassium iodide | lead(II) nitrate | potassium nitrate | lead iodide molar mass | 166.0028 g/mol | 331.2 g/mol | 101.1 g/mol | 461 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 681 °C | 470 °C | 334 °C | 402 °C boiling point | 1330 °C | | | 954 °C density | 3.123 g/cm^3 | | | 6.16 g/cm^3 solubility in water | | | soluble | dynamic viscosity | 0.0010227 Pa s (at 732.9 °C) | | | odor | | odorless | odorless |