Input interpretation
![magnesium phosphate | molar mass](../image_source/ec3ac64f24ebe0e027a3f874e63160ac.png)
magnesium phosphate | molar mass
Result
![Find the molar mass, M, for magnesium phosphate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: MgHPO_4·3H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 1 Mg (magnesium) | 1 O (oxygen) | 4 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 1 | 1.008 Mg (magnesium) | 1 | 24.305 O (oxygen) | 4 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 Mg (magnesium) | 1 | 24.305 | 1 × 24.305 = 24.305 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 1.008 g/mol + 24.305 g/mol + 63.996 g/mol + 30.973761998 g/mol = 120.283 g/mol](../image_source/c76a68558ef2e4a078e9a565c439691b.png)
Find the molar mass, M, for magnesium phosphate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: MgHPO_4·3H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 1 Mg (magnesium) | 1 O (oxygen) | 4 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 1 | 1.008 Mg (magnesium) | 1 | 24.305 O (oxygen) | 4 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 Mg (magnesium) | 1 | 24.305 | 1 × 24.305 = 24.305 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 1.008 g/mol + 24.305 g/mol + 63.996 g/mol + 30.973761998 g/mol = 120.283 g/mol
Unit conversion
![0.12028 kg/mol (kilograms per mole)](../image_source/73b208c130cea93fdf47e6b8db41f46c.png)
0.12028 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.17 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/c5c238f3807b6c63825c064126cbdf63.png)
≈ ( 0.17 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.62 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/0ef99914278bce66c1b4bd1889cd86c9.png)
≈ 0.62 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/07bfb199931e244b6169c1d8ddcd1bfb.png)
≈ 2.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2×10^-22 grams | 2×10^-25 kg (kilograms) | 120 u (unified atomic mass units) | 120 Da (daltons)](../image_source/91110edd5e433d8c1b3274ec6efa78a0.png)
Mass of a molecule m from m = M/N_A: | 2×10^-22 grams | 2×10^-25 kg (kilograms) | 120 u (unified atomic mass units) | 120 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 120](../image_source/9795d4577cd8b0026995d642a7682b46.png)
Relative molecular mass M_r from M_r = M_u/M: | 120