Input interpretation
![iron(III) chloride hexahydrate | molar mass](../image_source/4dd10e9796927e126a73a7cb69d67887.png)
iron(III) chloride hexahydrate | molar mass
Result
![Find the molar mass, M, for iron(III) chloride hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FeCl_3·6H_2O Use the chemical formula, FeCl_3·6H_2O, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 Fe (iron) | 1 H (hydrogen) | 12 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 Fe (iron) | 1 | 55.845 H (hydrogen) | 12 | 1.008 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 Fe (iron) | 1 | 55.845 | 1 × 55.845 = 55.845 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 106.35 g/mol + 55.845 g/mol + 12.096 g/mol + 95.994 g/mol = 270.29 g/mol](../image_source/d0bf5c2ac6f6d3a874d1859f335d1459.png)
Find the molar mass, M, for iron(III) chloride hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FeCl_3·6H_2O Use the chemical formula, FeCl_3·6H_2O, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 Fe (iron) | 1 H (hydrogen) | 12 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 Fe (iron) | 1 | 55.845 H (hydrogen) | 12 | 1.008 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 Fe (iron) | 1 | 55.845 | 1 × 55.845 = 55.845 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 106.35 g/mol + 55.845 g/mol + 12.096 g/mol + 95.994 g/mol = 270.29 g/mol
Unit conversion
![0.2703 kg/mol (kilograms per mole)](../image_source/775db31c31804ad4950575ba6ea7640d.png)
0.2703 kg/mol (kilograms per mole)
Comparisons
![≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/2aec69311b882205940378e92f872103.png)
≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/91d02a94241ea054cd3678f507e098b8.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/024553f1a232a1e9cd5a86e42383ffad.png)
≈ 4.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.5×10^-22 grams | 4.5×10^-25 kg (kilograms) | 270 u (unified atomic mass units) | 270 Da (daltons)](../image_source/1632223d66155421f6354858c1a36f78.png)
Mass of a molecule m from m = M/N_A: | 4.5×10^-22 grams | 4.5×10^-25 kg (kilograms) | 270 u (unified atomic mass units) | 270 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 270](../image_source/c2cda7d36b461bc8d2fc424deed0b3c7.png)
Relative molecular mass M_r from M_r = M_u/M: | 270