Input interpretation
nitric acid + copper(II) ferrous sulfide ⟶ water + sulfuric acid + nitric oxide + copper(II) nitrate + ferric nitrate
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Cu, Fe and S: H: | c_1 = 2 c_3 + 2 c_4 N: | c_1 = c_5 + 2 c_6 + 3 c_7 O: | 3 c_1 = c_3 + 4 c_4 + c_5 + 6 c_6 + 9 c_7 Cu: | c_2 = c_6 Fe: | c_2 = c_7 S: | 2 c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 32/3 c_2 = 1 c_3 = 10/3 c_4 = 2 c_5 = 17/3 c_6 = 1 c_7 = 1 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 32 c_2 = 3 c_3 = 10 c_4 = 6 c_5 = 17 c_6 = 3 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 32 + 3 ⟶ 10 + 6 + 17 + 3 + 3
Structures
+ ⟶ + + + +
Names
nitric acid + copper(II) ferrous sulfide ⟶ water + sulfuric acid + nitric oxide + copper(II) nitrate + ferric nitrate