Input interpretation
1-azido-1-deoxy-β-D-glucopyranoside tetraacetate | molar mass
Result
Find the molar mass, M, for 1-azido-1-deoxy-β-D-glucopyranoside tetraacetate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_19N_3O_9 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 14 O (oxygen) | 9 N (nitrogen) | 3 H (hydrogen) | 19 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 14 | 12.011 O (oxygen) | 9 | 15.999 N (nitrogen) | 3 | 14.007 H (hydrogen) | 19 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 H (hydrogen) | 19 | 1.008 | 19 × 1.008 = 19.152 M = 168.154 g/mol + 143.991 g/mol + 42.021 g/mol + 19.152 g/mol = 373.318 g/mol
Unit conversion
0.3733 kg/mol (kilograms per mole)
Comparisons
≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 6.2×10^-22 grams | 6.2×10^-25 kg (kilograms) | 373 u (unified atomic mass units) | 373 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 373