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mass fractions of ferrous oxalate

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ferrous oxalate | elemental composition
ferrous oxalate | elemental composition

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Find the elemental composition for ferrous oxalate in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: C_2FeO_4 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule:  | number of atoms  C (carbon) | 2  Fe (iron) | 1  O (oxygen) | 4  N_atoms = 2 + 1 + 4 = 7 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work:  | number of atoms | atom fraction  C (carbon) | 2 | 2/7  Fe (iron) | 1 | 1/7  O (oxygen) | 4 | 4/7 Check: 2/7 + 1/7 + 4/7 = 1 Compute atom percents using the atom fractions:  | number of atoms | atom percent  C (carbon) | 2 | 2/7 × 100% = 28.6%  Fe (iron) | 1 | 1/7 × 100% = 14.3%  O (oxygen) | 4 | 4/7 × 100% = 57.1% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | number of atoms | atom percent | atomic mass/u  C (carbon) | 2 | 28.6% | 12.011  Fe (iron) | 1 | 14.3% | 55.845  O (oxygen) | 4 | 57.1% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m:  | number of atoms | atom percent | atomic mass/u | mass/u  C (carbon) | 2 | 28.6% | 12.011 | 2 × 12.011 = 24.022  Fe (iron) | 1 | 14.3% | 55.845 | 1 × 55.845 = 55.845  O (oxygen) | 4 | 57.1% | 15.999 | 4 × 15.999 = 63.996  m = 24.022 u + 55.845 u + 63.996 u = 143.863 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work:  | number of atoms | atom percent | mass fraction  C (carbon) | 2 | 28.6% | 24.022/143.863  Fe (iron) | 1 | 14.3% | 55.845/143.863  O (oxygen) | 4 | 57.1% | 63.996/143.863 Check: 24.022/143.863 + 55.845/143.863 + 63.996/143.863 = 1 Compute mass percents using the mass fractions: Answer: |   | | number of atoms | atom percent | mass percent  C (carbon) | 2 | 28.6% | 24.022/143.863 × 100% = 16.70%  Fe (iron) | 1 | 14.3% | 55.845/143.863 × 100% = 38.82%  O (oxygen) | 4 | 57.1% | 63.996/143.863 × 100% = 44.48%
Find the elemental composition for ferrous oxalate in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: C_2FeO_4 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms C (carbon) | 2 Fe (iron) | 1 O (oxygen) | 4 N_atoms = 2 + 1 + 4 = 7 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction C (carbon) | 2 | 2/7 Fe (iron) | 1 | 1/7 O (oxygen) | 4 | 4/7 Check: 2/7 + 1/7 + 4/7 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent C (carbon) | 2 | 2/7 × 100% = 28.6% Fe (iron) | 1 | 1/7 × 100% = 14.3% O (oxygen) | 4 | 4/7 × 100% = 57.1% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u C (carbon) | 2 | 28.6% | 12.011 Fe (iron) | 1 | 14.3% | 55.845 O (oxygen) | 4 | 57.1% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u C (carbon) | 2 | 28.6% | 12.011 | 2 × 12.011 = 24.022 Fe (iron) | 1 | 14.3% | 55.845 | 1 × 55.845 = 55.845 O (oxygen) | 4 | 57.1% | 15.999 | 4 × 15.999 = 63.996 m = 24.022 u + 55.845 u + 63.996 u = 143.863 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction C (carbon) | 2 | 28.6% | 24.022/143.863 Fe (iron) | 1 | 14.3% | 55.845/143.863 O (oxygen) | 4 | 57.1% | 63.996/143.863 Check: 24.022/143.863 + 55.845/143.863 + 63.996/143.863 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent C (carbon) | 2 | 28.6% | 24.022/143.863 × 100% = 16.70% Fe (iron) | 1 | 14.3% | 55.845/143.863 × 100% = 38.82% O (oxygen) | 4 | 57.1% | 63.996/143.863 × 100% = 44.48%

Mass fraction pie chart

Mass fraction pie chart
Mass fraction pie chart