Input interpretation
![1-ethynyl-2, 4-difluorobenzene | molar mass](../image_source/d3034014732bbfa10346be92f4bb1ad6.png)
1-ethynyl-2, 4-difluorobenzene | molar mass
Result
![Find the molar mass, M, for 1-ethynyl-2, 4-difluorobenzene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HC congruent CC_6H_3F_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 F (fluorine) | 2 H (hydrogen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 4 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 M = 96.088 g/mol + 37.996806326 g/mol + 4.032 g/mol = 138.117 g/mol](../image_source/6149850f32a50f82c5b86feff49040ba.png)
Find the molar mass, M, for 1-ethynyl-2, 4-difluorobenzene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HC congruent CC_6H_3F_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 F (fluorine) | 2 H (hydrogen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 4 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 M = 96.088 g/mol + 37.996806326 g/mol + 4.032 g/mol = 138.117 g/mol
Unit conversion
![0.13812 kg/mol (kilograms per mole)](../image_source/e3f76515511495224c763d318bd53be6.png)
0.13812 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/feb7d1dd94aadf43a6ec52ac8da971ac.png)
≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.71 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/725e21121e9e63b25dd609bf9b536069.png)
≈ 0.71 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/a905eac492bf4259b7737949c963fd85.png)
≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.3×10^-22 grams | 2.3×10^-25 kg (kilograms) | 138 u (unified atomic mass units) | 138 Da (daltons)](../image_source/a99b0ccd48b7392768164328f96d8ff3.png)
Mass of a molecule m from m = M/N_A: | 2.3×10^-22 grams | 2.3×10^-25 kg (kilograms) | 138 u (unified atomic mass units) | 138 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 138](../image_source/0a29b8842e14691903f249b4b66bc13b.png)
Relative molecular mass M_r from M_r = M_u/M: | 138