Input interpretation
![(S)-(-)-2-(tert-butoxycarbonylamino)-3-cyclohexyl-1-propanol | molar mass](../image_source/b4653255f216b4cae00f417fb5709a23.png)
(S)-(-)-2-(tert-butoxycarbonylamino)-3-cyclohexyl-1-propanol | molar mass
Result
![Find the molar mass, M, for (S)-(-)-2-(tert-butoxycarbonylamino)-3-cyclohexyl-1-propanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_11CH_2CH[NHCO_2C(CH_3)_3]CH_2OH Use the chemical formula, C_6H_11CH_2CH[NHCO_2C(CH_3)_3]CH_2OH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 14 H (hydrogen) | 27 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 14 | 12.011 H (hydrogen) | 27 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 H (hydrogen) | 27 | 1.008 | 27 × 1.008 = 27.216 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 168.154 g/mol + 27.216 g/mol + 14.007 g/mol + 47.997 g/mol = 257.374 g/mol](../image_source/a02036091209ccb3da19917577a04df9.png)
Find the molar mass, M, for (S)-(-)-2-(tert-butoxycarbonylamino)-3-cyclohexyl-1-propanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_11CH_2CH[NHCO_2C(CH_3)_3]CH_2OH Use the chemical formula, C_6H_11CH_2CH[NHCO_2C(CH_3)_3]CH_2OH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 14 H (hydrogen) | 27 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 14 | 12.011 H (hydrogen) | 27 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 H (hydrogen) | 27 | 1.008 | 27 × 1.008 = 27.216 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 168.154 g/mol + 27.216 g/mol + 14.007 g/mol + 47.997 g/mol = 257.374 g/mol
Unit conversion
![0.25737 kg/mol (kilograms per mole)](../image_source/37b5a8de1b79b7a3aabc8392ff9192e0.png)
0.25737 kg/mol (kilograms per mole)
Comparisons
![≈ 0.36 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/d9e6716746ebe772466636d3412a888f.png)
≈ 0.36 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/13fabafe4311333d7b84f43630c9d676.png)
≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/0fb745b385fbd4edb8e803c77d538250.png)
≈ 4.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.3×10^-22 grams | 4.3×10^-25 kg (kilograms) | 257 u (unified atomic mass units) | 257 Da (daltons)](../image_source/dbe7338a02041623271c57831a671930.png)
Mass of a molecule m from m = M/N_A: | 4.3×10^-22 grams | 4.3×10^-25 kg (kilograms) | 257 u (unified atomic mass units) | 257 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 257](../image_source/267140e11f4eea36ce5b23a60ddd284f.png)
Relative molecular mass M_r from M_r = M_u/M: | 257