Input interpretation
tantalum(V) oxide | molar mass
Result
Find the molar mass, M, for tantalum(V) oxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ta_2O_5 Use the chemical formula, Ta_2O_5, to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 5 Ta (tantalum) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 5 | 15.999 Ta (tantalum) | 2 | 180.94788 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 Ta (tantalum) | 2 | 180.94788 | 2 × 180.94788 = 361.89576 M = 79.995 g/mol + 361.89576 g/mol = 441.891 g/mol
Unit conversion
0.441891 kg/mol (kilograms per mole)
Comparisons
≈ 0.61 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 7.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 7.3×10^-22 grams | 7.3×10^-25 kg (kilograms) | 442 u (unified atomic mass units) | 442 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 442