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H2O + NH4NO3 = HNO3 + NH4OH

Input interpretation

H_2O water + NH_4NO_3 ammonium nitrate ⟶ HNO_3 nitric acid + NH_4OH ammonium hydroxide
H_2O water + NH_4NO_3 ammonium nitrate ⟶ HNO_3 nitric acid + NH_4OH ammonium hydroxide

Balanced equation

Balance the chemical equation algebraically: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 NH_4NO_3 ⟶ c_3 HNO_3 + c_4 NH_4OH Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and N: H: | 2 c_1 + 4 c_2 = c_3 + 5 c_4 O: | c_1 + 3 c_2 = 3 c_3 + c_4 N: | 2 c_2 = c_3 + c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH
Balance the chemical equation algebraically: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 NH_4NO_3 ⟶ c_3 HNO_3 + c_4 NH_4OH Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and N: H: | 2 c_1 + 4 c_2 = c_3 + 5 c_4 O: | c_1 + 3 c_2 = 3 c_3 + c_4 N: | 2 c_2 = c_3 + c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH

Structures

+ ⟶ +
+ ⟶ +

Names

water + ammonium nitrate ⟶ nitric acid + ammonium hydroxide
water + ammonium nitrate ⟶ nitric acid + ammonium hydroxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NH_4NO_3 | 1 | -1 HNO_3 | 1 | 1 NH_4OH | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 1 | -1 | ([H2O])^(-1) NH_4NO_3 | 1 | -1 | ([NH4NO3])^(-1) HNO_3 | 1 | 1 | [HNO3] NH_4OH | 1 | 1 | [NH4OH] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-1) ([NH4NO3])^(-1) [HNO3] [NH4OH] = ([HNO3] [NH4OH])/([H2O] [NH4NO3])
Construct the equilibrium constant, K, expression for: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NH_4NO_3 | 1 | -1 HNO_3 | 1 | 1 NH_4OH | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 1 | -1 | ([H2O])^(-1) NH_4NO_3 | 1 | -1 | ([NH4NO3])^(-1) HNO_3 | 1 | 1 | [HNO3] NH_4OH | 1 | 1 | [NH4OH] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-1) ([NH4NO3])^(-1) [HNO3] [NH4OH] = ([HNO3] [NH4OH])/([H2O] [NH4NO3])

Rate of reaction

Construct the rate of reaction expression for: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NH_4NO_3 | 1 | -1 HNO_3 | 1 | 1 NH_4OH | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 1 | -1 | -(Δ[H2O])/(Δt) NH_4NO_3 | 1 | -1 | -(Δ[NH4NO3])/(Δt) HNO_3 | 1 | 1 | (Δ[HNO3])/(Δt) NH_4OH | 1 | 1 | (Δ[NH4OH])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2O])/(Δt) = -(Δ[NH4NO3])/(Δt) = (Δ[HNO3])/(Δt) = (Δ[NH4OH])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O + NH_4NO_3 ⟶ HNO_3 + NH_4OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NH_4NO_3 | 1 | -1 HNO_3 | 1 | 1 NH_4OH | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 1 | -1 | -(Δ[H2O])/(Δt) NH_4NO_3 | 1 | -1 | -(Δ[NH4NO3])/(Δt) HNO_3 | 1 | 1 | (Δ[HNO3])/(Δt) NH_4OH | 1 | 1 | (Δ[NH4OH])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2O])/(Δt) = -(Δ[NH4NO3])/(Δt) = (Δ[HNO3])/(Δt) = (Δ[NH4OH])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| water | ammonium nitrate | nitric acid | ammonium hydroxide formula | H_2O | NH_4NO_3 | HNO_3 | NH_4OH Hill formula | H_2O | H_4N_2O_3 | HNO_3 | H_5NO name | water | ammonium nitrate | nitric acid | ammonium hydroxide
| water | ammonium nitrate | nitric acid | ammonium hydroxide formula | H_2O | NH_4NO_3 | HNO_3 | NH_4OH Hill formula | H_2O | H_4N_2O_3 | HNO_3 | H_5NO name | water | ammonium nitrate | nitric acid | ammonium hydroxide

Substance properties

| water | ammonium nitrate | nitric acid | ammonium hydroxide molar mass | 18.015 g/mol | 80.04 g/mol | 63.012 g/mol | 35.046 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | aqueous (at STP) melting point | 0 °C | 169 °C | -41.6 °C | -57.5 °C boiling point | 99.9839 °C | 210 °C | 83 °C | 36 °C density | 1 g/cm^3 | 1.73 g/cm^3 | 1.5129 g/cm^3 | 0.9 g/cm^3 solubility in water | | | miscible | very soluble surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 7.6×10^-4 Pa s (at 25 °C) | odor | odorless | odorless | |
| water | ammonium nitrate | nitric acid | ammonium hydroxide molar mass | 18.015 g/mol | 80.04 g/mol | 63.012 g/mol | 35.046 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | aqueous (at STP) melting point | 0 °C | 169 °C | -41.6 °C | -57.5 °C boiling point | 99.9839 °C | 210 °C | 83 °C | 36 °C density | 1 g/cm^3 | 1.73 g/cm^3 | 1.5129 g/cm^3 | 0.9 g/cm^3 solubility in water | | | miscible | very soluble surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 7.6×10^-4 Pa s (at 25 °C) | odor | odorless | odorless | |

Units

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