Search

volume of 12 kg of terbium

Input interpretation

convert 12 kg of terbium (chemical element) to volume
convert 12 kg of terbium (chemical element) to volume

Results

1.46 L (liters)
1.46 L (liters)

Possible intermediate steps

Convert from kilograms into liters: 12 kg of Tb (terbium) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 8.219 g/cm^3 (grams per cubic centimeter) at STP of Tb: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(8.219 g) = 1460 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (1460 cm^3)/1 × (1 mL)/(1 cm^3) = 1460 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: |   | (1460 mL)/1 × (1 L)/(1000 mL) = 1.46 L
Convert from kilograms into liters: 12 kg of Tb (terbium) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 8.219 g/cm^3 (grams per cubic centimeter) at STP of Tb: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(8.219 g) = 1460 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (1460 cm^3)/1 × (1 mL)/(1 cm^3) = 1460 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: | | (1460 mL)/1 × (1 L)/(1000 mL) = 1.46 L

Unit conversions

0.00146 m^3 (cubic meters)
0.00146 m^3 (cubic meters)
1460 cm^3 (cubic centimeters)
1460 cm^3 (cubic centimeters)
49.37 fl oz (fluid ounces)
49.37 fl oz (fluid ounces)
3.086 pints
3.086 pints
1.543 quarts
1.543 quarts
0.3857 gallons
0.3857 gallons
0.05156 ft^3 (cubic feet)
0.05156 ft^3 (cubic feet)
89.1 in^3 (cubic inches)
89.1 in^3 (cubic inches)

Comparisons as volume

 ≈ ( 0.065 ≈ 1/15 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
≈ ( 0.065 ≈ 1/15 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
 ≈ 3 × volume of a typical human breath ( ≈ 0.5 L )
≈ 3 × volume of a typical human breath ( ≈ 0.5 L )
 ≈ 23 × volume of an Apple iPhone 4 ( ≈ 6.3×10^-5 m^3 )
≈ 23 × volume of an Apple iPhone 4 ( ≈ 6.3×10^-5 m^3 )

Comparisons as volume of food or beverage

 ≈ 0.47 × volume of a US size 10 can ( 105 fl oz )
≈ 0.47 × volume of a US size 10 can ( 105 fl oz )
 ≈ 0.88 × volume of a US size 5 can ( 7 cups )
≈ 0.88 × volume of a US size 5 can ( 7 cups )
 ≈ 1.5 × volume of a US size 3 can ( 4 cups )
≈ 1.5 × volume of a US size 3 can ( 4 cups )

Interpretations

volume
volume
volume of food or beverage
volume of food or beverage
capacity
capacity
section modulus
section modulus

Basic unit dimensions

[length]^3
[length]^3

Corresponding quantities

Radius r of a sphere from V = 4πr^3/3:  | 70 mm (millimeters)  | 0.23 feet  | 2.8 inches
Radius r of a sphere from V = 4πr^3/3: | 70 mm (millimeters) | 0.23 feet | 2.8 inches
Edge length a of a cube from V = a^3:  | 11 cm (centimeters)  | 0.37 feet  | 4.5 inches
Edge length a of a cube from V = a^3: | 11 cm (centimeters) | 0.37 feet | 4.5 inches
Mass m of water from m = ρ_(H_2O)V:  | 1.5 kg (kilograms)  | 3.2 lb (pounds)  | (assuming maximum water density ≈ 1000 kg/m^3)
Mass m of water from m = ρ_(H_2O)V: | 1.5 kg (kilograms) | 3.2 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O):  | 4.881×10^25 molecules  | (assuming maximum water density ≈ 1000 kg/m^3)  | (assuming molecular mass of water ≈ 18.02 u)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 4.881×10^25 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)