Input interpretation
![(5z, 9e, 14z)-(8xi, 11r, 12s)-11, 12-epoxy-8-hydroxyicosa-5, 9, 14-trienoate | molar mass](../image_source/39849e21edb188fa08ea005f52c7d2d8.png)
(5z, 9e, 14z)-(8xi, 11r, 12s)-11, 12-epoxy-8-hydroxyicosa-5, 9, 14-trienoate | molar mass
Result
![Find the molar mass, M, for (5z, 9e, 14z)-(8xi, 11r, 12s)-11, 12-epoxy-8-hydroxyicosa-5, 9, 14-trienoate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_32O_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 20 H (hydrogen) | 31 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 20 | 12.011 H (hydrogen) | 31 | 1.008 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220 H (hydrogen) | 31 | 1.008 | 31 × 1.008 = 31.248 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 240.220 g/mol + 31.248 g/mol + 63.996 g/mol = 335.464 g/mol](../image_source/f252c736a8dca8cff24bf0595b2a81c7.png)
Find the molar mass, M, for (5z, 9e, 14z)-(8xi, 11r, 12s)-11, 12-epoxy-8-hydroxyicosa-5, 9, 14-trienoate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_32O_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 20 H (hydrogen) | 31 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 20 | 12.011 H (hydrogen) | 31 | 1.008 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220 H (hydrogen) | 31 | 1.008 | 31 × 1.008 = 31.248 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 240.220 g/mol + 31.248 g/mol + 63.996 g/mol = 335.464 g/mol
Unit conversion
![0.33546 kg/mol (kilograms per mole)](../image_source/ee42a264cbce82232c5bddadc2e51ea7.png)
0.33546 kg/mol (kilograms per mole)
Comparisons
![≈ 0.47 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/6b99f2888bee6efe85a54c001a8a422e.png)
≈ 0.47 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/5e9c3255c01a0c4195ef6355d64c48a1.png)
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/752ea7662e6daf24549d2c5cee60972f.png)
≈ 5.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.6×10^-22 grams | 5.6×10^-25 kg (kilograms) | 335 u (unified atomic mass units) | 335 Da (daltons)](../image_source/fc79dbd8b8f5d3d2034bb95f0d1c6cd6.png)
Mass of a molecule m from m = M/N_A: | 5.6×10^-22 grams | 5.6×10^-25 kg (kilograms) | 335 u (unified atomic mass units) | 335 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 335](../image_source/33bbd26d64ac147a6e6c149b8900d854.png)
Relative molecular mass M_r from M_r = M_u/M: | 335