Input interpretation
copper(II) chromite | molar mass
Result
Find the molar mass, M, for copper(II) chromite: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CuCr_2O_4 Use the chemical formula, CuCr_2O_4, to count the number of atoms, N_i, for each element: | N_i Cr (chromium) | 1 Cu (copper) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cr (chromium) | 1 | 51.9961 Cu (copper) | 1 | 63.546 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 51.9961 g/mol + 63.546 g/mol + 47.997 g/mol = 163.539 g/mol
Unit conversion
0.16354 kg/mol (kilograms per mole)
Comparisons
≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.84 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 164 u (unified atomic mass units) | 164 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 164