Input interpretation
thulium(III) oxalate | molar mass
Result
Find the molar mass, M, for thulium(III) oxalate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6O_12Tm_2 Use the chemical formula, C_6O_12Tm_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 O (oxygen) | 12 Tm (thulium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 O (oxygen) | 12 | 15.999 Tm (thulium) | 2 | 168.93422 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 O (oxygen) | 12 | 15.999 | 12 × 15.999 = 191.988 Tm (thulium) | 2 | 168.93422 | 2 × 168.93422 = 337.86844 M = 72.066 g/mol + 191.988 g/mol + 337.86844 g/mol = 601.922 g/mol
Unit conversion
0.60192 kg/mol (kilograms per mole)
Comparisons
≈ 0.84 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 3.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 10 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1×10^-21 grams | 1×10^-24 kg (kilograms) | 602 u (unified atomic mass units) | 602 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 602