Input interpretation
tetrairidium dodecacarbonyl | molar mass
Result
Find the molar mass, M, for tetrairidium dodecacarbonyl: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ir_4(CO)_12 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 Ir (iridium) | 4 O (oxygen) | 12 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 Ir (iridium) | 4 | 192.217 O (oxygen) | 12 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 Ir (iridium) | 4 | 192.217 | 4 × 192.217 = 768.868 O (oxygen) | 12 | 15.999 | 12 × 15.999 = 191.988 M = 144.132 g/mol + 768.868 g/mol + 191.988 g/mol = 1104.988 g/mol
Unit conversion
1.105 kg/mol (kilograms per mole)
Comparisons
≈ 1.5 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 5.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 19 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.8×10^-21 grams | 1.8×10^-24 kg (kilograms) | 1105 u (unified atomic mass units) | 1.1 kDa (kilodaltons)
Relative molecular mass M_r from M_r = M_u/M: | 1105