Input interpretation
azure II eosinate | molar mass
Result
![Find the molar mass, M, for azure II eosinate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: [(CH_3)_2(N=)(C_12H_6NS)N(CH_3)_2Cl][(CH_3)_2(N=)(C_12H_6NS)NH(CH_3)Cl][C_20H_6Br_4O_5Na_2] Use the chemical formula, [(CH_3)_2(N=)(C_12H_6NS)N(CH_3)_2Cl][(CH_3)_2(N=)(C_12H_6NS)NH(CH_3)Cl][C_20H_6Br_4O_5Na_2], to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 4 C (carbon) | 51 Cl (chlorine) | 2 H (hydrogen) | 40 N (nitrogen) | 6 Na (sodium) | 2 O (oxygen) | 5 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 4 | 79.904 C (carbon) | 51 | 12.011 Cl (chlorine) | 2 | 35.45 H (hydrogen) | 40 | 1.008 N (nitrogen) | 6 | 14.007 Na (sodium) | 2 | 22.98976928 O (oxygen) | 5 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 4 | 79.904 | 4 × 79.904 = 319.616 C (carbon) | 51 | 12.011 | 51 × 12.011 = 612.561 Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 H (hydrogen) | 40 | 1.008 | 40 × 1.008 = 40.320 N (nitrogen) | 6 | 14.007 | 6 × 14.007 = 84.042 Na (sodium) | 2 | 22.98976928 | 2 × 22.98976928 = 45.97953856 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 319.616 g/mol + 612.561 g/mol + 70.90 g/mol + 40.320 g/mol + 84.042 g/mol + 45.97953856 g/mol + 79.995 g/mol + 64.12 g/mol = 1317.53 g/mol](../image_source/ce1831e1e4e2c08c7efea504054ffda9.png)
Find the molar mass, M, for azure II eosinate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: [(CH_3)_2(N=)(C_12H_6NS)N(CH_3)_2Cl][(CH_3)_2(N=)(C_12H_6NS)NH(CH_3)Cl][C_20H_6Br_4O_5Na_2] Use the chemical formula, [(CH_3)_2(N=)(C_12H_6NS)N(CH_3)_2Cl][(CH_3)_2(N=)(C_12H_6NS)NH(CH_3)Cl][C_20H_6Br_4O_5Na_2], to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 4 C (carbon) | 51 Cl (chlorine) | 2 H (hydrogen) | 40 N (nitrogen) | 6 Na (sodium) | 2 O (oxygen) | 5 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 4 | 79.904 C (carbon) | 51 | 12.011 Cl (chlorine) | 2 | 35.45 H (hydrogen) | 40 | 1.008 N (nitrogen) | 6 | 14.007 Na (sodium) | 2 | 22.98976928 O (oxygen) | 5 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 4 | 79.904 | 4 × 79.904 = 319.616 C (carbon) | 51 | 12.011 | 51 × 12.011 = 612.561 Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 H (hydrogen) | 40 | 1.008 | 40 × 1.008 = 40.320 N (nitrogen) | 6 | 14.007 | 6 × 14.007 = 84.042 Na (sodium) | 2 | 22.98976928 | 2 × 22.98976928 = 45.97953856 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 319.616 g/mol + 612.561 g/mol + 70.90 g/mol + 40.320 g/mol + 84.042 g/mol + 45.97953856 g/mol + 79.995 g/mol + 64.12 g/mol = 1317.53 g/mol
Unit conversion
1.3175 kg/mol (kilograms per mole)
Comparisons
≈ 1.8 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 6.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 23 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 2.2×10^-21 grams | 2.2×10^-24 kg (kilograms) | 1318 u (unified atomic mass units) | 1.3 kDa (kilodaltons)
Relative molecular mass M_r from M_r = M_u/M: | 1318