Input interpretation
H_2SO_4 sulfuric acid + K_2Cr_2O_7 potassium dichromate + Na_2C_2O_4 sodium oxalate ⟶ H_2O water + CO_2 carbon dioxide + K_2SO_4 potassium sulfate + Na_2SO_4 sodium sulfate + Cr_2(SO_4)_3 chromium sulfate
Balanced equation
Balance the chemical equation algebraically: H_2SO_4 + K_2Cr_2O_7 + Na_2C_2O_4 ⟶ H_2O + CO_2 + K_2SO_4 + Na_2SO_4 + Cr_2(SO_4)_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 K_2Cr_2O_7 + c_3 Na_2C_2O_4 ⟶ c_4 H_2O + c_5 CO_2 + c_6 K_2SO_4 + c_7 Na_2SO_4 + c_8 Cr_2(SO_4)_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr, K, C and Na: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_2 + 4 c_3 = c_4 + 2 c_5 + 4 c_6 + 4 c_7 + 12 c_8 S: | c_1 = c_6 + c_7 + 3 c_8 Cr: | 2 c_2 = 2 c_8 K: | 2 c_2 = 2 c_6 C: | 2 c_3 = c_5 Na: | 2 c_3 = 2 c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 7 c_2 = 1 c_3 = 3 c_4 = 7 c_5 = 6 c_6 = 1 c_7 = 3 c_8 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 7 H_2SO_4 + K_2Cr_2O_7 + 3 Na_2C_2O_4 ⟶ 7 H_2O + 6 CO_2 + K_2SO_4 + 3 Na_2SO_4 + Cr_2(SO_4)_3