Search

H2O + CaOHNO3 = HNO3 + Ca(OH)2

Input interpretation

H_2O water + CaOHNO3 ⟶ HNO_3 nitric acid + Ca(OH)_2 calcium hydroxide
H_2O water + CaOHNO3 ⟶ HNO_3 nitric acid + Ca(OH)_2 calcium hydroxide

Balanced equation

Balance the chemical equation algebraically: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 CaOHNO3 ⟶ c_3 HNO_3 + c_4 Ca(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Ca and N: H: | 2 c_1 + c_2 = c_3 + 2 c_4 O: | c_1 + 4 c_2 = 3 c_3 + 2 c_4 Ca: | c_2 = c_4 N: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2
Balance the chemical equation algebraically: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 CaOHNO3 ⟶ c_3 HNO_3 + c_4 Ca(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Ca and N: H: | 2 c_1 + c_2 = c_3 + 2 c_4 O: | c_1 + 4 c_2 = 3 c_3 + 2 c_4 Ca: | c_2 = c_4 N: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2

Structures

+ CaOHNO3 ⟶ +
+ CaOHNO3 ⟶ +

Names

water + CaOHNO3 ⟶ nitric acid + calcium hydroxide
water + CaOHNO3 ⟶ nitric acid + calcium hydroxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 CaOHNO3 | 1 | -1 HNO_3 | 1 | 1 Ca(OH)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 1 | -1 | ([H2O])^(-1) CaOHNO3 | 1 | -1 | ([CaOHNO3])^(-1) HNO_3 | 1 | 1 | [HNO3] Ca(OH)_2 | 1 | 1 | [Ca(OH)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-1) ([CaOHNO3])^(-1) [HNO3] [Ca(OH)2] = ([HNO3] [Ca(OH)2])/([H2O] [CaOHNO3])
Construct the equilibrium constant, K, expression for: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 CaOHNO3 | 1 | -1 HNO_3 | 1 | 1 Ca(OH)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 1 | -1 | ([H2O])^(-1) CaOHNO3 | 1 | -1 | ([CaOHNO3])^(-1) HNO_3 | 1 | 1 | [HNO3] Ca(OH)_2 | 1 | 1 | [Ca(OH)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-1) ([CaOHNO3])^(-1) [HNO3] [Ca(OH)2] = ([HNO3] [Ca(OH)2])/([H2O] [CaOHNO3])

Rate of reaction

Construct the rate of reaction expression for: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 CaOHNO3 | 1 | -1 HNO_3 | 1 | 1 Ca(OH)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 1 | -1 | -(Δ[H2O])/(Δt) CaOHNO3 | 1 | -1 | -(Δ[CaOHNO3])/(Δt) HNO_3 | 1 | 1 | (Δ[HNO3])/(Δt) Ca(OH)_2 | 1 | 1 | (Δ[Ca(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2O])/(Δt) = -(Δ[CaOHNO3])/(Δt) = (Δ[HNO3])/(Δt) = (Δ[Ca(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O + CaOHNO3 ⟶ HNO_3 + Ca(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 CaOHNO3 | 1 | -1 HNO_3 | 1 | 1 Ca(OH)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 1 | -1 | -(Δ[H2O])/(Δt) CaOHNO3 | 1 | -1 | -(Δ[CaOHNO3])/(Δt) HNO_3 | 1 | 1 | (Δ[HNO3])/(Δt) Ca(OH)_2 | 1 | 1 | (Δ[Ca(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2O])/(Δt) = -(Δ[CaOHNO3])/(Δt) = (Δ[HNO3])/(Δt) = (Δ[Ca(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| water | CaOHNO3 | nitric acid | calcium hydroxide formula | H_2O | CaOHNO3 | HNO_3 | Ca(OH)_2 Hill formula | H_2O | HCaNO4 | HNO_3 | CaH_2O_2 name | water | | nitric acid | calcium hydroxide IUPAC name | water | | nitric acid | calcium dihydroxide
| water | CaOHNO3 | nitric acid | calcium hydroxide formula | H_2O | CaOHNO3 | HNO_3 | Ca(OH)_2 Hill formula | H_2O | HCaNO4 | HNO_3 | CaH_2O_2 name | water | | nitric acid | calcium hydroxide IUPAC name | water | | nitric acid | calcium dihydroxide

Substance properties

| water | CaOHNO3 | nitric acid | calcium hydroxide molar mass | 18.015 g/mol | 119.09 g/mol | 63.012 g/mol | 74.092 g/mol phase | liquid (at STP) | | liquid (at STP) | solid (at STP) melting point | 0 °C | | -41.6 °C | 550 °C boiling point | 99.9839 °C | | 83 °C | density | 1 g/cm^3 | | 1.5129 g/cm^3 | 2.24 g/cm^3 solubility in water | | | miscible | slightly soluble surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 7.6×10^-4 Pa s (at 25 °C) | odor | odorless | | | odorless
| water | CaOHNO3 | nitric acid | calcium hydroxide molar mass | 18.015 g/mol | 119.09 g/mol | 63.012 g/mol | 74.092 g/mol phase | liquid (at STP) | | liquid (at STP) | solid (at STP) melting point | 0 °C | | -41.6 °C | 550 °C boiling point | 99.9839 °C | | 83 °C | density | 1 g/cm^3 | | 1.5129 g/cm^3 | 2.24 g/cm^3 solubility in water | | | miscible | slightly soluble surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 7.6×10^-4 Pa s (at 25 °C) | odor | odorless | | | odorless

Units

Random Queries

alternate names of ethylene glycol monobutyl ether acetate vs 1,2-(ethylenedioxy)benzene
electron affinities of period 4 elements
net ionic charge of actinium cation
H2O + SO2 + H3AsO4 = H2SO4 + H3AsO3
atomic radius of bismuth vs hafnium
indium vs strontium vs molybdenum
freezing point of potassium perchlorate
first ionization energy of fermium vs thorium
liquid densities of lanthanides
color platinum