Input interpretation
![sulfuric acid + sodium sulfide + sodium bichromate ⟶ water + mixed sulfur + sodium sulfate + chromium sulfate](../image_source/8adcb893ab4ab6e2914037652acd286b.png)
sulfuric acid + sodium sulfide + sodium bichromate ⟶ water + mixed sulfur + sodium sulfate + chromium sulfate
Balanced equation
![Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Na and Cr: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_3 = c_4 + 4 c_6 + 12 c_7 S: | c_1 + c_2 = c_5 + c_6 + 3 c_7 Na: | 2 c_2 + 2 c_3 = 2 c_6 Cr: | 2 c_3 = 2 c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_2 = (3 c_1)/16 + 9/16 c_3 = c_1/4 - 1/4 c_4 = c_1 c_5 = 1 c_6 = (7 c_1)/16 + 5/16 c_7 = c_1/4 - 1/4 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 13 and solve for the remaining coefficients: c_1 = 13 c_2 = 3 c_3 = 3 c_4 = 13 c_5 = 1 c_6 = 6 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 13 + 3 + 3 ⟶ 13 + + 6 + 3](../image_source/0db3bbb759bd5d985b8533efee107980.png)
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Na and Cr: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_3 = c_4 + 4 c_6 + 12 c_7 S: | c_1 + c_2 = c_5 + c_6 + 3 c_7 Na: | 2 c_2 + 2 c_3 = 2 c_6 Cr: | 2 c_3 = 2 c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_2 = (3 c_1)/16 + 9/16 c_3 = c_1/4 - 1/4 c_4 = c_1 c_5 = 1 c_6 = (7 c_1)/16 + 5/16 c_7 = c_1/4 - 1/4 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 13 and solve for the remaining coefficients: c_1 = 13 c_2 = 3 c_3 = 3 c_4 = 13 c_5 = 1 c_6 = 6 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 13 + 3 + 3 ⟶ 13 + + 6 + 3
Structures
![+ + ⟶ + + +](../image_source/3f324ecc1e62b219c9222a53b20c6f2e.png)
+ + ⟶ + + +
Names
![sulfuric acid + sodium sulfide + sodium bichromate ⟶ water + mixed sulfur + sodium sulfate + chromium sulfate](../image_source/80786c67567ce7f8aee61966e680a67d.png)
sulfuric acid + sodium sulfide + sodium bichromate ⟶ water + mixed sulfur + sodium sulfate + chromium sulfate
Chemical names and formulas
![| sulfuric acid | sodium sulfide | sodium bichromate | water | mixed sulfur | sodium sulfate | chromium sulfate Hill formula | H_2O_4S | Na_2S | Cr_2Na_2O_7 | H_2O | S | Na_2O_4S | Cr_2O_12S_3 name | sulfuric acid | sodium sulfide | sodium bichromate | water | mixed sulfur | sodium sulfate | chromium sulfate IUPAC name | sulfuric acid | | disodium oxido-(oxido-dioxo-chromio)oxy-dioxo-chromium | water | sulfur | disodium sulfate | chromium(+3) cation trisulfate](../image_source/dbd1a99f46cd715413ae53b084b5694e.png)
| sulfuric acid | sodium sulfide | sodium bichromate | water | mixed sulfur | sodium sulfate | chromium sulfate Hill formula | H_2O_4S | Na_2S | Cr_2Na_2O_7 | H_2O | S | Na_2O_4S | Cr_2O_12S_3 name | sulfuric acid | sodium sulfide | sodium bichromate | water | mixed sulfur | sodium sulfate | chromium sulfate IUPAC name | sulfuric acid | | disodium oxido-(oxido-dioxo-chromio)oxy-dioxo-chromium | water | sulfur | disodium sulfate | chromium(+3) cation trisulfate