hybridization of deuterated acetic acid (D4)

deuterated acetic acid (D4) | orbital hybridization

First draw the structure diagram for deuterated acetic acid (D4), and for every non-hydrogen atom, count the σ-bonds. Note that double and triple bonds consist of one σ-bond together with one or two π-bonds: Identify those atoms with lone pairs: Find the steric number by adding the lone pair count to the number of σ-bonds: Consult the following chart to determine the hybridization from the steric number: steric number | hybridization 2 | sp 3 | sp^2 4 | sp^3 5 | dsp^3 6 | d^2sp^3 7 | d^3sp^3 Assign the provisional hybridization based on the table: Next identify any sp^3 atoms with lone pair electrons which can participate in a conjugated π-bond system. These atoms can lower their energy by placing a lone pair in a unhybridized p orbital to maximize overlap with the neighboring π-bonds. Note that halogens and elements from the third period and below do not engage in bond conjugation, except in the case of aromaticity: Adjust the provisional hybridizations to arrive at the result: Answer: | |

formula | CD_3CO_2D Hill formula | C_2D_4O_2 name | deuterated acetic acid (D4) IUPAC name | 2, 2, 2-trideuterioacetic acid deuterio ester alternate names | 2, 2, 2-trideuterioacetic acid deuterio ester | [2H3]acetic [2H]acid | acetic acid-d4 | acetic-d3 acid-d | deuterio 2, 2, 2-trideuterioacetate | deuterio 2, 2, 2-trideuterioethanoate | tetradeuteroacetic acid mass fractions | O (oxygen) 0.499% | C (carbon) 0.375% | H (hydrogen) 0.126%