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molar mass of 2,3,7,8,12,13,17,18-octaethyl-21H,23 H-porphine copper(II)

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2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II) | molar mass
2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II) | molar mass

Result

Find the molar mass, M, for 2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_36H_46CuN_4)^2+ Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Cu (copper) | 1  C (carbon) | 36  N (nitrogen) | 4  H (hydrogen) | 46 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Cu (copper) | 1 | 63.546  C (carbon) | 36 | 12.011  N (nitrogen) | 4 | 14.007  H (hydrogen) | 46 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546  C (carbon) | 36 | 12.011 | 36 × 12.011 = 432.396  N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028  H (hydrogen) | 46 | 1.008 | 46 × 1.008 = 46.368  M = 63.546 g/mol + 432.396 g/mol + 56.028 g/mol + 46.368 g/mol = 598.338 g/mol
Find the molar mass, M, for 2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_36H_46CuN_4)^2+ Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cu (copper) | 1 C (carbon) | 36 N (nitrogen) | 4 H (hydrogen) | 46 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cu (copper) | 1 | 63.546 C (carbon) | 36 | 12.011 N (nitrogen) | 4 | 14.007 H (hydrogen) | 46 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546 C (carbon) | 36 | 12.011 | 36 × 12.011 = 432.396 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 H (hydrogen) | 46 | 1.008 | 46 × 1.008 = 46.368 M = 63.546 g/mol + 432.396 g/mol + 56.028 g/mol + 46.368 g/mol = 598.338 g/mol