Input interpretation
![D-glucose-13 C6, C-d 7 | molar mass](../image_source/1c6e6b58b58083e2f56131e6767b5ba4.png)
D-glucose-13 C6, C-d 7 | molar mass
Result
![Find the molar mass, M, for D-glucose-13 C6, C-d 7: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: 13C_6H_5D_7O_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 21 O (oxygen) | 4 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 21 | 1.008 O (oxygen) | 4 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 108.099 g/mol + 21.168 g/mol + 63.996 g/mol + 30.973761998 g/mol = 224.237 g/mol](../image_source/9e446791273d2e1cc3ef47dad67f18c8.png)
Find the molar mass, M, for D-glucose-13 C6, C-d 7: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: 13C_6H_5D_7O_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 21 O (oxygen) | 4 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 21 | 1.008 O (oxygen) | 4 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 108.099 g/mol + 21.168 g/mol + 63.996 g/mol + 30.973761998 g/mol = 224.237 g/mol
Unit conversion
![0.22424 kg/mol (kilograms per mole)](../image_source/ca908275071d59b8bc04366845c06fef.png)
0.22424 kg/mol (kilograms per mole)
Comparisons
![≈ 0.31 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/45bbd4489daf9d1842c6dd00bde67295.png)
≈ 0.31 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/f3116110d937b313e45526e06db30c44.png)
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/2d3622d4ae4867bc01a2681172af79db.png)
≈ 3.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.7×10^-22 grams | 3.7×10^-25 kg (kilograms) | 224 u (unified atomic mass units) | 224 Da (daltons)](../image_source/565a5c0bd01ab584c06f1ade4933a4f8.png)
Mass of a molecule m from m = M/N_A: | 3.7×10^-22 grams | 3.7×10^-25 kg (kilograms) | 224 u (unified atomic mass units) | 224 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 224](../image_source/57d4312bd07c8c6404656bc9d01ce9aa.png)
Relative molecular mass M_r from M_r = M_u/M: | 224