Input interpretation
molybdenum(IV) telluride | molar mass
Result
Find the molar mass, M, for molybdenum(IV) telluride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: MoTe_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Mo (molybdenum) | 1 Te (tellurium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Mo (molybdenum) | 1 | 95.95 Te (tellurium) | 2 | 127.60 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Mo (molybdenum) | 1 | 95.95 | 1 × 95.95 = 95.95 Te (tellurium) | 2 | 127.60 | 2 × 127.60 = 255.20 M = 95.95 g/mol + 255.20 g/mol = 351.15 g/mol
Unit conversion
0.3512 kg/mol (kilograms per mole)
Comparisons
≈ 0.49 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.8×10^-22 grams | 5.8×10^-25 kg (kilograms) | 351 u (unified atomic mass units) | 351 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 351