Input interpretation
![boron phosphate hydrate | molar mass](../image_source/d44d07a6d697ee8a79b6f87e44361568.png)
boron phosphate hydrate | molar mass
Result
![Find the molar mass, M, for boron phosphate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BPO_4·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 H (hydrogen) | 2 O (oxygen) | 5 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 H (hydrogen) | 2 | 1.008 O (oxygen) | 5 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 10.81 g/mol + 2.016 g/mol + 79.995 g/mol + 30.973761998 g/mol = 123.79 g/mol](../image_source/135aab3878ca8830b2a4bf2432213146.png)
Find the molar mass, M, for boron phosphate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BPO_4·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 H (hydrogen) | 2 O (oxygen) | 5 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 H (hydrogen) | 2 | 1.008 O (oxygen) | 5 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 10.81 g/mol + 2.016 g/mol + 79.995 g/mol + 30.973761998 g/mol = 123.79 g/mol
Unit conversion
![0.12379 kg/mol (kilograms per mole)](../image_source/0b9c609281738e842a3e8d5711773aaa.png)
0.12379 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.17 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/303bdbcaf9608de802b96e6f65c5e1e7.png)
≈ ( 0.17 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.64 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/74c626f01fac126d213a513865bfc0d3.png)
≈ 0.64 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/cd4b1ac1cf335b738214146e6570430d.png)
≈ 2.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.1×10^-22 grams | 2.1×10^-25 kg (kilograms) | 124 u (unified atomic mass units) | 124 Da (daltons)](../image_source/51d68085fcf702f7ec1b6aa590cf66fd.png)
Mass of a molecule m from m = M/N_A: | 2.1×10^-22 grams | 2.1×10^-25 kg (kilograms) | 124 u (unified atomic mass units) | 124 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 124](../image_source/86190cf6c8a0083f2423c5876674fefe.png)
Relative molecular mass M_r from M_r = M_u/M: | 124