hybridization of toluene

toluene | orbital hybridization

First draw the structure diagram for toluene, and for every non-hydrogen atom, count the σ-bonds. Note that double and triple bonds consist of one σ-bond together with one or two π-bonds: For toluene there are no lone pairs, so the steric number is given by the σ-bond count. Consult the following chart to determine the hybridization from the steric number: steric number | hybridization 2 | sp 3 | sp^2 4 | sp^3 5 | dsp^3 6 | d^2sp^3 7 | d^3sp^3 Now assign the hybridization for each atom: Answer: | |

formula | C_6H_5CH_3 Hill formula | C_7H_8 name | toluene IUPAC name | methylbenzene alternate names | meth acid e | methane, phenyl- | methylbenzene | methylbenzol | phenylmethane | toluol mass fractions | C (carbon) 91.2% | H (hydrogen) 8.75%