Input interpretation
ammonium metavanadate | molar mass
Result
Find the molar mass, M, for ammonium metavanadate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NH_4VO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 4 N (nitrogen) | 1 O (oxygen) | 3 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 4 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 4.032 g/mol + 14.007 g/mol + 47.997 g/mol + 50.9415 g/mol = 116.978 g/mol
Unit conversion
0.11698 kg/mol (kilograms per mole)
Comparisons
≈ ( 0.16 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.6 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.9×10^-22 grams | 1.9×10^-25 kg (kilograms) | 117 u (unified atomic mass units) | 117 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 117