Input interpretation
gadolinium(III) telluride | molar mass
Result
Find the molar mass, M, for gadolinium(III) telluride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Gd_2Te_3 Use the chemical formula, Gd_2Te_3, to count the number of atoms, N_i, for each element: | N_i Gd (gadolinium) | 2 Te (tellurium) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Gd (gadolinium) | 2 | 157.25 Te (tellurium) | 3 | 127.60 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Gd (gadolinium) | 2 | 157.25 | 2 × 157.25 = 314.50 Te (tellurium) | 3 | 127.60 | 3 × 127.60 = 382.80 M = 314.50 g/mol + 382.80 g/mol = 697.30 g/mol
Unit conversion
0.6973 kg/mol (kilograms per mole)
Comparisons
≈ 0.97 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 3.6 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 12 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.2×10^-21 grams | 1.2×10^-24 kg (kilograms) | 697 u (unified atomic mass units) | 697 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 697