H2SO4 + BaO2 = H2O2 + BaSO4

H_2SO_4 (sulfuric acid) + BaO_2 (barium peroxide) ⟶ H_2O_2 (hydrogen peroxide) + BaSO_4 (barium sulfate)

Balance the chemical equation algebraically: H_2SO_4 + BaO_2 ⟶ H_2O_2 + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 BaO_2 ⟶ c_3 H_2O_2 + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S and Ba: H: | 2 c_1 = 2 c_3 O: | 4 c_1 + 2 c_2 = 2 c_3 + 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2SO_4 + BaO_2 ⟶ H_2O_2 + BaSO_4

+ ⟶ +

sulfuric acid + barium peroxide ⟶ hydrogen peroxide + barium sulfate

Construct the equilibrium constant, K, expression for: H_2SO_4 + BaO_2 ⟶ H_2O_2 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + BaO_2 ⟶ H_2O_2 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 BaO_2 | 1 | -1 H_2O_2 | 1 | 1 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) BaO_2 | 1 | -1 | ([BaO2])^(-1) H_2O_2 | 1 | 1 | [H2O2] BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-1) ([BaO2])^(-1) [H2O2] [BaSO4] = ([H2O2] [BaSO4])/([H2SO4] [BaO2])

Construct the rate of reaction expression for: H_2SO_4 + BaO_2 ⟶ H_2O_2 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + BaO_2 ⟶ H_2O_2 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 BaO_2 | 1 | -1 H_2O_2 | 1 | 1 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) BaO_2 | 1 | -1 | -(Δ[BaO2])/(Δt) H_2O_2 | 1 | 1 | (Δ[H2O2])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2SO4])/(Δt) = -(Δ[BaO2])/(Δt) = (Δ[H2O2])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| sulfuric acid | barium peroxide | hydrogen peroxide | barium sulfate formula | H_2SO_4 | BaO_2 | H_2O_2 | BaSO_4 Hill formula | H_2O_4S | BaO_2 | H_2O_2 | BaO_4S name | sulfuric acid | barium peroxide | hydrogen peroxide | barium sulfate IUPAC name | sulfuric acid | barium(+2) cation peroxide | hydrogen peroxide | barium(+2) cation sulfate

| sulfuric acid | barium peroxide | hydrogen peroxide | barium sulfate molar mass | 98.07 g/mol | 169.325 g/mol | 34.014 g/mol | 233.38 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 10.371 °C | 450 °C | -0.43 °C | 1345 °C boiling point | 279.6 °C | | 150.2 °C | density | 1.8305 g/cm^3 | 4.96 g/cm^3 | 1.44 g/cm^3 | 4.5 g/cm^3 solubility in water | very soluble | slightly soluble | miscible | insoluble surface tension | 0.0735 N/m | | 0.0804 N/m | dynamic viscosity | 0.021 Pa s (at 25 °C) | | 0.001249 Pa s (at 20 °C) | odor | odorless | | |