Input interpretation
![diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide | molecular mass](../image_source/1e10b31b1903057a657824774948e3b3.png)
diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide | molecular mass
Result
![Find the molecular mass, m, for diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_30N_2O_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 22 H (hydrogen) | 30 N (nitrogen) | 2 O (oxygen) | 3 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 22 | 12.011 H (hydrogen) | 30 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242 H (hydrogen) | 30 | 1.008 | 30 × 1.008 = 30.240 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 m = 264.242 u + 30.240 u + 28.014 u + 47.997 u = 370.493 u](../image_source/555d85c3e1eb9ae396844d5403606eab.png)
Find the molecular mass, m, for diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_30N_2O_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 22 H (hydrogen) | 30 N (nitrogen) | 2 O (oxygen) | 3 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 22 | 12.011 H (hydrogen) | 30 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242 H (hydrogen) | 30 | 1.008 | 30 × 1.008 = 30.240 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 m = 264.242 u + 30.240 u + 28.014 u + 47.997 u = 370.493 u
Unit conversions
370.49 Da (daltons)
0.37049 kDa (kilodaltons)
6.152×10^-22 grams
6.152×10^-25 kg (kilograms)
370.51 chemical atomic mass units (unit officially deprecated)
370.61 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
≈ 0.51 × molecular mass of fullerene ( ≈ 721 u )
≈ 1.9 × molecular mass of caffeine ( ≈ 194 u )
≈ 6.3 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 370
Molar mass M from M = m_aN_A: | 370 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 370
Molar mass M from M = m_mN_A: | 370 g/mol (grams per mole)