Input interpretation
![diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide | molecular mass](../image_source/1e10b31b1903057a657824774948e3b3.png)
diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide | molecular mass
Result
![Find the molecular mass, m, for diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_30N_2O_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 22 H (hydrogen) | 30 N (nitrogen) | 2 O (oxygen) | 3 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 22 | 12.011 H (hydrogen) | 30 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242 H (hydrogen) | 30 | 1.008 | 30 × 1.008 = 30.240 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 m = 264.242 u + 30.240 u + 28.014 u + 47.997 u = 370.493 u](../image_source/555d85c3e1eb9ae396844d5403606eab.png)
Find the molecular mass, m, for diazene, bis[4-(pentyloxy)phenyl]-, 1-oxide: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_30N_2O_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 22 H (hydrogen) | 30 N (nitrogen) | 2 O (oxygen) | 3 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 22 | 12.011 H (hydrogen) | 30 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242 H (hydrogen) | 30 | 1.008 | 30 × 1.008 = 30.240 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 m = 264.242 u + 30.240 u + 28.014 u + 47.997 u = 370.493 u
Unit conversions
![370.49 Da (daltons)](../image_source/69219ddcf15cc4c85b8272a3d2841d14.png)
370.49 Da (daltons)
![0.37049 kDa (kilodaltons)](../image_source/6fdbe1e75fccdb9234eb7ca0cfb762dd.png)
0.37049 kDa (kilodaltons)
![6.152×10^-22 grams](../image_source/139e5eac5db3cacc9b6f4b3208657fcd.png)
6.152×10^-22 grams
![6.152×10^-25 kg (kilograms)](../image_source/5b39d76ae02035c149464c851ffc3527.png)
6.152×10^-25 kg (kilograms)
![370.51 chemical atomic mass units (unit officially deprecated)](../image_source/9c45bc3fc15fde28b0e58cd1c9fc357f.png)
370.51 chemical atomic mass units (unit officially deprecated)
![370.61 physical atomic mass units (unit officially deprecated)](../image_source/99c38265ed52cb1c3cdd43ea8de424af.png)
370.61 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
![≈ 0.51 × molecular mass of fullerene ( ≈ 721 u )](../image_source/8f2b1e131c49a4d596fe92624196ef08.png)
≈ 0.51 × molecular mass of fullerene ( ≈ 721 u )
![≈ 1.9 × molecular mass of caffeine ( ≈ 194 u )](../image_source/44b158564b5737cc6077f505318f7956.png)
≈ 1.9 × molecular mass of caffeine ( ≈ 194 u )
![≈ 6.3 × molecular mass of sodium chloride ( ≈ 58 u )](../image_source/798d315bb82c84c277f599950873e048.png)
≈ 6.3 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
![Relative atomic mass A_r from A_r = m_aN_A/M_u: | 370](../image_source/a105f9d1e2a7765ca535b296d21e7414.png)
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 370
![Molar mass M from M = m_aN_A: | 370 g/mol (grams per mole)](../image_source/f60966c21e1d65f8fb7df3b84c54094c.png)
Molar mass M from M = m_aN_A: | 370 g/mol (grams per mole)
![Relative molecular mass M_r from M_r = m_mN_A/M_u: | 370](../image_source/b76ca56c7ec5e298957ad81b7da2c890.png)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 370
![Molar mass M from M = m_mN_A: | 370 g/mol (grams per mole)](../image_source/b9518d2da419f509902ea3e3d6e5d4b2.png)
Molar mass M from M = m_mN_A: | 370 g/mol (grams per mole)