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H2CO3 + LiOH = H2O + Li2CO3

Input interpretation

H_2CO_3 carbonic acid + LiOH lithium hydroxide ⟶ H_2O water + Li_2CO_3 lithium carbonate
H_2CO_3 carbonic acid + LiOH lithium hydroxide ⟶ H_2O water + Li_2CO_3 lithium carbonate

Balanced equation

Balance the chemical equation algebraically: H_2CO_3 + LiOH ⟶ H_2O + Li_2CO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2CO_3 + c_2 LiOH ⟶ c_3 H_2O + c_4 Li_2CO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for C, H, O and Li: C: | c_1 = c_4 H: | 2 c_1 + c_2 = 2 c_3 O: | 3 c_1 + c_2 = c_3 + 3 c_4 Li: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | H_2CO_3 + 2 LiOH ⟶ 2 H_2O + Li_2CO_3
Balance the chemical equation algebraically: H_2CO_3 + LiOH ⟶ H_2O + Li_2CO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2CO_3 + c_2 LiOH ⟶ c_3 H_2O + c_4 Li_2CO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for C, H, O and Li: C: | c_1 = c_4 H: | 2 c_1 + c_2 = 2 c_3 O: | 3 c_1 + c_2 = c_3 + 3 c_4 Li: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2CO_3 + 2 LiOH ⟶ 2 H_2O + Li_2CO_3

Structures

 + ⟶ +
+ ⟶ +

Names

carbonic acid + lithium hydroxide ⟶ water + lithium carbonate
carbonic acid + lithium hydroxide ⟶ water + lithium carbonate

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2CO_3 + LiOH ⟶ H_2O + Li_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2CO_3 + 2 LiOH ⟶ 2 H_2O + Li_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2CO_3 | 1 | -1 LiOH | 2 | -2 H_2O | 2 | 2 Li_2CO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2CO_3 | 1 | -1 | ([H2CO3])^(-1) LiOH | 2 | -2 | ([LiOH])^(-2) H_2O | 2 | 2 | ([H2O])^2 Li_2CO_3 | 1 | 1 | [Li2CO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2CO3])^(-1) ([LiOH])^(-2) ([H2O])^2 [Li2CO3] = (([H2O])^2 [Li2CO3])/([H2CO3] ([LiOH])^2)
Construct the equilibrium constant, K, expression for: H_2CO_3 + LiOH ⟶ H_2O + Li_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2CO_3 + 2 LiOH ⟶ 2 H_2O + Li_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2CO_3 | 1 | -1 LiOH | 2 | -2 H_2O | 2 | 2 Li_2CO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2CO_3 | 1 | -1 | ([H2CO3])^(-1) LiOH | 2 | -2 | ([LiOH])^(-2) H_2O | 2 | 2 | ([H2O])^2 Li_2CO_3 | 1 | 1 | [Li2CO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2CO3])^(-1) ([LiOH])^(-2) ([H2O])^2 [Li2CO3] = (([H2O])^2 [Li2CO3])/([H2CO3] ([LiOH])^2)

Rate of reaction

Construct the rate of reaction expression for: H_2CO_3 + LiOH ⟶ H_2O + Li_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2CO_3 + 2 LiOH ⟶ 2 H_2O + Li_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2CO_3 | 1 | -1 LiOH | 2 | -2 H_2O | 2 | 2 Li_2CO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2CO_3 | 1 | -1 | -(Δ[H2CO3])/(Δt) LiOH | 2 | -2 | -1/2 (Δ[LiOH])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) Li_2CO_3 | 1 | 1 | (Δ[Li2CO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[H2CO3])/(Δt) = -1/2 (Δ[LiOH])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[Li2CO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2CO_3 + LiOH ⟶ H_2O + Li_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2CO_3 + 2 LiOH ⟶ 2 H_2O + Li_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2CO_3 | 1 | -1 LiOH | 2 | -2 H_2O | 2 | 2 Li_2CO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2CO_3 | 1 | -1 | -(Δ[H2CO3])/(Δt) LiOH | 2 | -2 | -1/2 (Δ[LiOH])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) Li_2CO_3 | 1 | 1 | (Δ[Li2CO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2CO3])/(Δt) = -1/2 (Δ[LiOH])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[Li2CO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | carbonic acid | lithium hydroxide | water | lithium carbonate formula | H_2CO_3 | LiOH | H_2O | Li_2CO_3 Hill formula | CH_2O_3 | HLiO | H_2O | CLi_2O_3 name | carbonic acid | lithium hydroxide | water | lithium carbonate IUPAC name | carbonic acid | lithium hydroxide | water | dilithium carbonate
| carbonic acid | lithium hydroxide | water | lithium carbonate formula | H_2CO_3 | LiOH | H_2O | Li_2CO_3 Hill formula | CH_2O_3 | HLiO | H_2O | CLi_2O_3 name | carbonic acid | lithium hydroxide | water | lithium carbonate IUPAC name | carbonic acid | lithium hydroxide | water | dilithium carbonate

Substance properties

 | carbonic acid | lithium hydroxide | water | lithium carbonate molar mass | 62.024 g/mol | 23.95 g/mol | 18.015 g/mol | 73.9 g/mol phase | | solid (at STP) | liquid (at STP) | solid (at STP) melting point | | 462 °C | 0 °C | 618 °C boiling point | | | 99.9839 °C |  density | | 1.46 g/cm^3 | 1 g/cm^3 | 2.11 g/cm^3 surface tension | | | 0.0728 N/m |  dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) |  odor | | odorless | odorless |
| carbonic acid | lithium hydroxide | water | lithium carbonate molar mass | 62.024 g/mol | 23.95 g/mol | 18.015 g/mol | 73.9 g/mol phase | | solid (at STP) | liquid (at STP) | solid (at STP) melting point | | 462 °C | 0 °C | 618 °C boiling point | | | 99.9839 °C | density | | 1.46 g/cm^3 | 1 g/cm^3 | 2.11 g/cm^3 surface tension | | | 0.0728 N/m | dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) | odor | | odorless | odorless |

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