Input interpretation
oxygen + ferrous sulfide ⟶ sulfur dioxide + iron(II) oxide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, Fe and S: O: | 2 c_1 = 2 c_3 + c_4 Fe: | c_2 = c_4 S: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 1 c_3 = 1 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 2 c_3 = 2 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 + 2 ⟶ 2 + 2
Structures
+ ⟶ +
Names
oxygen + ferrous sulfide ⟶ sulfur dioxide + iron(II) oxide
Reaction thermodynamics
Enthalpy
| oxygen | ferrous sulfide | sulfur dioxide | iron(II) oxide molecular enthalpy | 0 kJ/mol | -100 kJ/mol | -296.8 kJ/mol | -272 kJ/mol total enthalpy | 0 kJ/mol | -200 kJ/mol | -593.6 kJ/mol | -544 kJ/mol | H_initial = -200 kJ/mol | | H_final = -1138 kJ/mol | ΔH_rxn^0 | -1138 kJ/mol - -200 kJ/mol = -937.6 kJ/mol (exothermic) | | |
Gibbs free energy
| oxygen | ferrous sulfide | sulfur dioxide | iron(II) oxide molecular free energy | 231.7 kJ/mol | -100.4 kJ/mol | -300.1 kJ/mol | -255 kJ/mol total free energy | 695.1 kJ/mol | -200.8 kJ/mol | -600.2 kJ/mol | -510 kJ/mol | G_initial = 494.3 kJ/mol | | G_final = -1110 kJ/mol | ΔG_rxn^0 | -1110 kJ/mol - 494.3 kJ/mol = -1605 kJ/mol (exergonic) | | |
Entropy
| oxygen | ferrous sulfide | sulfur dioxide | iron(II) oxide molecular entropy | 205 J/(mol K) | 67 J/(mol K) | 248 J/(mol K) | 61 J/(mol K) total entropy | 615 J/(mol K) | 134 J/(mol K) | 496 J/(mol K) | 122 J/(mol K) | S_initial = 749 J/(mol K) | | S_final = 618 J/(mol K) | ΔS_rxn^0 | 618 J/(mol K) - 749 J/(mol K) = -131 J/(mol K) (exoentropic) | | |
Chemical names and formulas
| oxygen | ferrous sulfide | sulfur dioxide | iron(II) oxide Hill formula | O_2 | FeS | O_2S | FeO name | oxygen | ferrous sulfide | sulfur dioxide | iron(II) oxide IUPAC name | molecular oxygen | | sulfur dioxide | oxoiron