H2SO4 + K2Cr2O7 + SnCl2 = H2O + K2SO4 + Cr2(SO4)3 + SnCl4 + Sn(SO4)2

Input interpretation

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sulfuric acid + potassium dichromate + stannous chloride ⟶ water + potassium sulfate + chromium sulfate + stannic chloride + Sn(SO4)2

Balanced equation

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$Balance the chemical equation algebraically: + + ⟶ + + + + Sn(SO4)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 + c_8 Sn(SO4)2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr, K, Cl and Sn: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_2 = c_4 + 4 c_5 + 12 c_6 + 8 c_8 S: | c_1 = c_5 + 3 c_6 + 2 c_8 Cr: | 2 c_2 = 2 c_6 K: | 2 c_2 = 2 c_5 Cl: | 2 c_3 = 4 c_7 Sn: | c_3 = c_7 + c_8 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 7 c_2 = 1 c_3 = 3 c_4 = 7 c_5 = 1 c_6 = 1 c_7 = 3/2 c_8 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 14 c_2 = 2 c_3 = 6 c_4 = 14 c_5 = 2 c_6 = 2 c_7 = 3 c_8 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 14 + 2 + 6 ⟶ 14 + 2 + 2 + 3 + 3 Sn(SO4)2$

Balance the chemical equation algebraically: + + ⟶ + + + + Sn(SO4)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 + c_8 Sn(SO4)2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr, K, Cl and Sn: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_2 = c_4 + 4 c_5 + 12 c_6 + 8 c_8 S: | c_1 = c_5 + 3 c_6 + 2 c_8 Cr: | 2 c_2 = 2 c_6 K: | 2 c_2 = 2 c_5 Cl: | 2 c_3 = 4 c_7 Sn: | c_3 = c_7 + c_8 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 7 c_2 = 1 c_3 = 3 c_4 = 7 c_5 = 1 c_6 = 1 c_7 = 3/2 c_8 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 14 c_2 = 2 c_3 = 6 c_4 = 14 c_5 = 2 c_6 = 2 c_7 = 3 c_8 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 14 + 2 + 6 ⟶ 14 + 2 + 2 + 3 + 3 Sn(SO4)2