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molar mass of lithium 2-thienylcyanocuprate

Input interpretation

lithium 2-thienylcyanocuprate | molar mass
lithium 2-thienylcyanocuprate | molar mass

Result

Find the molar mass, M, for lithium 2-thienylcyanocuprate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_5H_3CuLiNS Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 5  Cu (copper) | 1  H (hydrogen) | 3  Li (lithium) | 1  N (nitrogen) | 1  S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 5 | 12.011  Cu (copper) | 1 | 63.546  H (hydrogen) | 3 | 1.008  Li (lithium) | 1 | 6.94  N (nitrogen) | 1 | 14.007  S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055  Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546  H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024  Li (lithium) | 1 | 6.94 | 1 × 6.94 = 6.94  N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007  S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06  M = 60.055 g/mol + 63.546 g/mol + 3.024 g/mol + 6.94 g/mol + 14.007 g/mol + 32.06 g/mol = 179.63 g/mol
Find the molar mass, M, for lithium 2-thienylcyanocuprate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_5H_3CuLiNS Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 5 Cu (copper) | 1 H (hydrogen) | 3 Li (lithium) | 1 N (nitrogen) | 1 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 5 | 12.011 Cu (copper) | 1 | 63.546 H (hydrogen) | 3 | 1.008 Li (lithium) | 1 | 6.94 N (nitrogen) | 1 | 14.007 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 Li (lithium) | 1 | 6.94 | 1 × 6.94 = 6.94 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 60.055 g/mol + 63.546 g/mol + 3.024 g/mol + 6.94 g/mol + 14.007 g/mol + 32.06 g/mol = 179.63 g/mol

Unit conversion

0.1796 kg/mol (kilograms per mole)
0.1796 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.25 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.25 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.93 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.93 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3×10^-22 grams  | 3×10^-25 kg (kilograms)  | 180 u (unified atomic mass units)  | 180 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3×10^-22 grams | 3×10^-25 kg (kilograms) | 180 u (unified atomic mass units) | 180 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 180
Relative molecular mass M_r from M_r = M_u/M: | 180