F2 + NH4UF5 = N2 + HF + UF6

fluorine + NH4UF5 ⟶ nitrogen + hydrogen fluoride + uranium hexafluoride

Balance the chemical equation algebraically: + NH4UF5 ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 NH4UF5 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for F, N, H and U: F: | 2 c_1 + 5 c_2 = c_4 + 6 c_5 N: | c_2 = 2 c_3 H: | 4 c_2 = c_4 U: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 5 c_2 = 2 c_3 = 1 c_4 = 8 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 5 + 2 NH4UF5 ⟶ + 8 + 2

+ NH4UF5 ⟶ + +

fluorine + NH4UF5 ⟶ nitrogen + hydrogen fluoride + uranium hexafluoride

| fluorine | NH4UF5 | nitrogen | hydrogen fluoride | uranium hexafluoride formula | | NH4UF5 | | | Hill formula | F_2 | H4F5NU | N_2 | FH | F_6U name | fluorine | | nitrogen | hydrogen fluoride | uranium hexafluoride IUPAC name | molecular fluorine | | molecular nitrogen | hydrogen fluoride | hexafluorouranium

| fluorine | NH4UF5 | nitrogen | hydrogen fluoride | uranium hexafluoride molar mass | 37.996806326 g/mol | 351.06 g/mol | 28.014 g/mol | 20.006 g/mol | 352.01933 g/mol phase | gas (at STP) | | gas (at STP) | gas (at STP) | solid (at STP) melting point | -219.6 °C | | -210 °C | -83.36 °C | 64 °C boiling point | -188.12 °C | | -195.79 °C | 19.5 °C | density | 0.001696 g/cm^3 (at 0 °C) | | 0.001251 g/cm^3 (at 0 °C) | 8.18×10^-4 g/cm^3 (at 25 °C) | 5.09 g/cm^3 solubility in water | reacts | | insoluble | miscible | surface tension | | | 0.0066 N/m | | dynamic viscosity | 2.344×10^-5 Pa s (at 25 °C) | | 1.78×10^-5 Pa s (at 25 °C) | 1.2571×10^-5 Pa s (at 20 °C) | 2.6×10^-5 Pa s (at 200 °C) odor | | | odorless | |