Search

molar mass of metanil yellow

Input interpretation

metanil yellow | molar mass
metanil yellow | molar mass

Result

Find the molar mass, M, for metanil yellow: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_18H_14N_3NaO_3S Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 18  H (hydrogen) | 14  N (nitrogen) | 3  Na (sodium) | 1  O (oxygen) | 3  S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 18 | 12.011  H (hydrogen) | 14 | 1.008  N (nitrogen) | 3 | 14.007  Na (sodium) | 1 | 22.98976928  O (oxygen) | 3 | 15.999  S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 18 | 12.011 | 18 × 12.011 = 216.198  H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112  N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021  Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06  M = 216.198 g/mol + 14.112 g/mol + 42.021 g/mol + 22.98976928 g/mol + 47.997 g/mol + 32.06 g/mol = 375.38 g/mol
Find the molar mass, M, for metanil yellow: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_18H_14N_3NaO_3S Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 18 H (hydrogen) | 14 N (nitrogen) | 3 Na (sodium) | 1 O (oxygen) | 3 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 18 | 12.011 H (hydrogen) | 14 | 1.008 N (nitrogen) | 3 | 14.007 Na (sodium) | 1 | 22.98976928 O (oxygen) | 3 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 18 | 12.011 | 18 × 12.011 = 216.198 H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 216.198 g/mol + 14.112 g/mol + 42.021 g/mol + 22.98976928 g/mol + 47.997 g/mol + 32.06 g/mol = 375.38 g/mol

Unit conversion

0.37538 kg/mol (kilograms per mole)
0.37538 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 6.2×10^-22 grams  | 6.2×10^-25 kg (kilograms)  | 375 u (unified atomic mass units)  | 375 Da (daltons)
Mass of a molecule m from m = M/N_A: | 6.2×10^-22 grams | 6.2×10^-25 kg (kilograms) | 375 u (unified atomic mass units) | 375 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 375
Relative molecular mass M_r from M_r = M_u/M: | 375